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Diano4ka-milaya [45]

3 years ago

13

Grant has 2 over 3 cup of ice cream in a bowl. He then removes two 1 over 6 cups of ice cream to share with his little brother.

Which of the following best explains the amount of ice cream left in Grant's bowl?
Please explain your answer

1 answer:

Nonamiya [84]3 years ago

6 0

I hope this helps you

2^3-2.1^6

8-2

6

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What is the area of circle? Show work !!!

Serjik [45]

Answer:

=615.44 m^2

Step-by-step explanation:

The area of the circle is given by

A = pi r^2

= pi (14)^2

= (3.14) 14^2

=615.44 m^2

6 0

3 years ago

In triangle abc, angle A is the right angle. What is the value of y?

Natalka [10]

Answer:

A

Step-by-step explanation:

In a right triangle, the side opposite to the 90 degree angle (here, side opposite to angle A) is known as the hypotenuse.

Also, the side that is "opposite" to the angle given (here side opposite is y to angle given 30 degrees) is the opposite side.

Since we want to find "opposite" and have "hypotenuse" , recalling trig ratios, we can say opposite/hypotenuse is the ratio SINE, so we can write:

$Sin(30)=\frac{y}{7}$

We solve for y:

$Sin(30)=\frac{y}{7}\\y = 7 Sin(30)$

Since the answer choice has angles in radians, we recall 30 degrees is $\frac{\pi}{6}$ radians.

Thus, the correct answer is $7Sin(\frac{\pi}{6})$ , or option A

3 0

4 years ago

Read 2 more answers

A company uses three different assembly lines- A1, A2, and A3- to manufacture a particular component. Of thosemanufactured by li

hammer [34]

Answer:

The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

Step-by-step explanation:

The three different assembly lines are: A₁, A₂ and A₃.

Denote <em>R</em> as the event that a component needs rework.

It is given that:

$P (R|A_{1})=0.05\\P (R|A_{2})=0.08\\P (R|A_{3})=0.10\\P (A_{1})=0.50\\P (A_{2})=0.30\\P (A_{3})=0.20$

Compute the probability that a randomly selected component needs rework as follows:

$P(R)=P(R|A_{1})P(A_{1})+P(R|A_{2})P(A_{2})+P(R|A_{3})P(A_{3})\\=(0.05\times0.50)+(0.08\times0.30)+(0.10\times0.20)\\=0.069$

Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

$P (A_{1}|R)=\frac{P(R|A_{1})P(A_{1})}{P(R)}=\frac{0.05\times0.50}{0.069} =0.3623$

Thus, the probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

6 0

3 years ago

Since 20% or 1/5, is ___, there will be ___ word problems on the test

VARVARA [1.3K]

Answer:

10

10

Step-by-step explanation:

One fifth of fifty is 10.

3 0

3 years ago

Find the value of the combination.<br><br> 21 C 3<br><br> 7,980<br> 2,660<br> 1,330

erik [133]

To evaluate the combination we proceed as follows:
21C3
Given nCk we shall have:
n!/[(n-k)!k!]
thus plugging the values in the expression we get:
21!/[(21-3)!3!]
=21!/(18!×3!)
=1330
Answer: 1330

4 0

3 years ago