so if 4 hours of math is 186, one hour is 46.5, therefore when you write a liner equation, you start with y=46.5x and then multiply 19 by 46.5
Answer:
the number of times in a month the train must be used, so that the total monthly cost without the pass is the same as the total monthly cost with the pass, is b. 24 times
Step-by-step explanation:
in normal purchase, train ticket (A) = $2.00
using frequent pass,
frequent pass (P) = $18
train ticket using frequent pass (B) = $1.25
Now, let assume the number of times in a month the train must be used = M
so,
A x M = P + (B x M)
$2.00 x M = $18 + ($1.25 x M)
($2.00 x M) - ($1.25 x M) = $18
M x ($2.00 - $1.25) = $18
M = $18 : $0.75
M = 24
Thus, the number of times in a month the train must be used is 24 times
Answer:
Picture of the problem? I can't solve without
Answer:
about 324 times.
Step-by-step explanation:
2400/7
342.857142857
