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2 years ago

What is 9 x 5 + 1 - 8

Mathematics

2 answers:

BlackZzzverrR [31]2 years ago

8 0

Answer:

es 38 la respuesta

Step-by-step explanation:

jjj ok lhhjjjhhghgghhhh

Liono4ka [1.6K]2 years ago

3 0

it will be 38

Step-by-step explanation:

because if you do 9x5 is give you 45 and add 1 gives you 46 and the if you subtract 8 if give you 38

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Y=3x-8 using function notation

maria [59]

To write it in function notation you'll convert it into a function, substituting y by f(x):

y = 3x - 8 = f(x) = 3x - 8

Hope it helped,

BioTeacher101

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3 years ago

0.66x10 to the 3rd power

Bas_tet [7]

The answer to this is 660

4 0

2 years ago

Read 2 more answers

Find the area of a rectangle with a width of x3 + 5x - 9 and a length of x2 + 8.

Drupady [299]

Answer:

A = x⁵ + 13x³ - 9x² + 40x - 72

Step-by-step explanation:

The formula for the area of a rectangle is length X width, or A = lw.

Substitute the equations for the sides into the formula:

A = lw

A = (x² + 8)(x³ + 5x - 9) <= use the distributive property

A = x⁵ + 5x³ -9x² + 8x³ + 40x - 72 <= collect like terms

A = x⁵ + 13x³ - 9x² + 40x - 72

4 0

3 years ago

a barrel of water contains 60 gallons of water if 21 gallons leaked out what percent of water was left in the barrel

adelina 88 [10]

Answer:

65% remains in the barrel

3 0

3 years ago

Read 2 more answers

Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

2 years ago