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In-s [12.5K]
2 years ago
13

Kevin has 3 bags of apples weighing a total of 22 1/2 pounds. Two of the bags weigh 6 3/8 pounds and 3 1/4 pounds. How much does

the third bag weigh?
A 11 7/8
B 12 4/8
C 12 7/8
D 13 5/8
Mathematics
2 answers:
xenn [34]2 years ago
8 0
All bags: 22 1/2 pounds
First bag: 6 3/8 pounds
Second bag: 3 1/4 pounds
Third bag: ???

First of all we need to find the common denominator for all the fractions.

22 1/2 = 22 4/8
3 1/4 = 3 2/8

Now we add both known bags and them substract the result from overall the weight:

6 3/8 + 3 2/8 = 9 5/8
22 4/8 - 9 5/8 = 12 7/8

So the answer is C.
Elena-2011 [213]2 years ago
6 0

Answer: C -12 7/8

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

  • <em>Total weight: 22 1/2 pounds </em>
  • <em>Bag 1 = 6 3/8 pounds </em>
  • <em>Bag 3 = 3 1/4 pounds </em>

First, we have to sum the weights of bag 1 and 2:

6 3/8 + 3 1/4=

6 3/8 + 3 2/8 = 9 5/8

Finally we subtract the number calculated to the total weight.

22 1/2 - 9 5/8=

22 4/8 -9 5/8=

21 (8/8 +4/8) - 9 5/8 =

21 12/8 - 9 5/8=

12 7/8

3rd bag weight: 12 7/8 pounds

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The weekly earnings of students in one age group are normally distributed with a standard deviation of 47 dollars. A researcher
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Answer:

Option D) 340

Step-by-step explanation:

We are given the following in the question:

Alpha, α = 0.05

Population standard deviation, σ = $47

Margin of error = 5

95% Confidence Interval:

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

\text{Margin of error} = z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

5 = 1.96(\dfrac{47}{\sqrt{n}} )\\\\\sqrt{n} = \dfrac{47\times 1.96}{5}\\\\n = 339.443776\\\Rightarrow n \approx 340

Thus, the correct answer is

Option D) 340

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