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In-s [12.5K]
2 years ago
13

Kevin has 3 bags of apples weighing a total of 22 1/2 pounds. Two of the bags weigh 6 3/8 pounds and 3 1/4 pounds. How much does

the third bag weigh?
A 11 7/8
B 12 4/8
C 12 7/8
D 13 5/8
Mathematics
2 answers:
xenn [34]2 years ago
8 0
All bags: 22 1/2 pounds
First bag: 6 3/8 pounds
Second bag: 3 1/4 pounds
Third bag: ???

First of all we need to find the common denominator for all the fractions.

22 1/2 = 22 4/8
3 1/4 = 3 2/8

Now we add both known bags and them substract the result from overall the weight:

6 3/8 + 3 2/8 = 9 5/8
22 4/8 - 9 5/8 = 12 7/8

So the answer is C.
Elena-2011 [213]2 years ago
6 0

Answer: C -12 7/8

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

  • <em>Total weight: 22 1/2 pounds </em>
  • <em>Bag 1 = 6 3/8 pounds </em>
  • <em>Bag 3 = 3 1/4 pounds </em>

First, we have to sum the weights of bag 1 and 2:

6 3/8 + 3 1/4=

6 3/8 + 3 2/8 = 9 5/8

Finally we subtract the number calculated to the total weight.

22 1/2 - 9 5/8=

22 4/8 -9 5/8=

21 (8/8 +4/8) - 9 5/8 =

21 12/8 - 9 5/8=

12 7/8

3rd bag weight: 12 7/8 pounds

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Answer:

\Large\boxed{\text{Perpendicular Equation:} \ y = -\frac{2}{7}x + \frac{22}{7}}

\Large\boxed{\text{Parallel Equation:} \ y = \frac{7}{2}x -12}

Step-by-step explanation:

In order to find the equations that are parallel/perpendicular to the line y = \frac{7}{2}x - 4, we need to note a couple things about the relationships between lines and their parallel/perpendicular lines.

  • A) If a line is perpendicular to another, the slopes will be opposite reciprocals (for instance -2 and \frac{1}{2} - multiplied, they equal -1.)
  • B) If a line is parallel to another, they will have the exact same slope.

<h2>Perpendicular:</h2>

We know that the slope of a perpendicular line will be the the opposite reciprocal of the line we're comparing it to.

Since the slope of our base line is \frac{7}{2}, we can find the reciprocal, then the opposite of that.

  • Reciprocal of \frac{7}{2} = \frac{2}{7}
  • Opposite of \frac{2}{7} = -\frac{2}{7}

So the slope of this line will be -\frac{2}{7}, making our equation y = -\frac{2}{7}x+ b

However, y-intercepts will not stay the same. In order to find this, we can substitute the point (4, 2) into our equation to solve for b.

  • 2 = -\frac{2}{7} \cdot 4 + b
  • 2 = -\frac{8}{7} + b
  • b = 2+\frac{8}{7}
  • b = 2 \frac{8}{7}
  • b=\frac{22}{7}

Now we know the y-intercept of this equation is \frac{22}{7}. We can now finish off our equation of the line by substituting that in to what we already have,  y = -\frac{2}{7}x+ b.

y = -\frac{2}{7}x+ \frac{22}{7}

<h2>Parallel:</h2>

As mentioned earlier, parallel lines will have the exact same slope but not the same y-intercept. Since the slope of our original equation is \frac{7}{2}, the slope for this one will also be \frac{7}{2}.

So we now know the equation looks something like y = \frac{7}{2}x + b.

In order to solve for b, we apply the same logic we did in the perpendicular line and substitute in the point (4, 2) into the equation.

  • 2 = \frac{7}{2} \cdot 4 + b
  • 2 = \frac{28}{2}+b
  • 2 = 14+b
  • b = 2-14
  • b =-12

Now that we know the slope and the y-intercept, we can finish off our equation as y = \frac{7}{2}x -12.

Hope this helped!

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