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Helen [10]
3 years ago
14

In a poll, 6 out of 13 children said they read every night before bed, whereas 54% of the adults said they read every night befo

re bed. Which group had a greater percentage of people who read before bed?
Mathematics
1 answer:
Tpy6a [65]3 years ago
3 0
To answer this question you must find the percentage of the children that read before bed and compare it to the adults bag read before bed’s percentage.
To do this, start by dividing the number of children that read before bed by the total number of children surveyed.
This leaves you with:
6/13= 0.4615

To find the actual percentage, multiply this result by 100.
0.4615 x 100 = 46.15
This percentage rounded is 46%

So, now you can compare the percentages. The percentage of children that read before bed is 46% and the percentage of adults that read before bed is 54%. So, the group with the greatest percentage was the adults.

I hope this helps!
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Use volume displacement to determine the volume of this metal sample to the nearest 0.1 ml.
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Will give branilst...Thank you in advance &lt;3
Alisiya [41]
It is the first option
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3 years ago
Jason with 120 and is going 10 pounds each month Gerardo weighs 150 pounds and is having 4 pounds each month . Write an equation
pshichka [43]

Answer:

5 months

Step-by-step explanation:

Jason's original weight = 120 pounds

Let the no. of months be m

If he gains 10 pounds in each moth , then his weight in m months will be = 10m

His total weight will be= 120+10m  -----(1)

Gerardo's original weight = 150 pounds

If he gains 4 pounds in each month , then his weight in m months will me =4m

His total weight will be = 150+4m-----(2)

<u>Equating (1) ans(2)</u>

120+10m=150+4m

=>10m-4m=150-120

=>6m=30

=>m=\frac{30}{6}

<u>=>m=5</u>

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5 0
3 years ago
Solve this 9(b+7)+29
blsea [12.9K]

9b+63+29

9b+92

Answer: 9b+92

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3 years ago
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