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Helen [10]
3 years ago
14

In a poll, 6 out of 13 children said they read every night before bed, whereas 54% of the adults said they read every night befo

re bed. Which group had a greater percentage of people who read before bed?
Mathematics
1 answer:
Tpy6a [65]3 years ago
3 0
To answer this question you must find the percentage of the children that read before bed and compare it to the adults bag read before bed’s percentage.
To do this, start by dividing the number of children that read before bed by the total number of children surveyed.
This leaves you with:
6/13= 0.4615

To find the actual percentage, multiply this result by 100.
0.4615 x 100 = 46.15
This percentage rounded is 46%

So, now you can compare the percentages. The percentage of children that read before bed is 46% and the percentage of adults that read before bed is 54%. So, the group with the greatest percentage was the adults.

I hope this helps!
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Answer:

Practice the worksheet on word problem on addition and subtraction.

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Step-by-step explanation:


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Step-by-step explanation:

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Answer:

\large\boxed{h=\dfrac{2A}{b_1+b_2}}

Step-by-step explanation:

A=\dfrac{1}{2}h(b_1+b_2)\qquad\text{multiply both sides by 2}\\\\2A=2\!\!\!\!\diagup\cdot\dfrac{1}{2\!\!\!\!\diagup}h(b_1+b_2)\\\\2A=h(b_1+b_2)\qquad\text{divide both sides by}\ (b_1+b_2)\\\\\dfrac{2A}{(b_1+b_2)}=\dfrac{h(b_1+b_2)}{(b_1+b_2)}\qquad\text{cancel}\ (b_1+b_2)\\\\\dfrac{2A}{b_1+b_2}=h\to h=\dfrac{2A}{b_1+b_2}

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