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neonofarm [45]
3 years ago
7

Need help with a math question

Mathematics
2 answers:
olga55 [171]3 years ago
7 0

ANSWER

{(x  + 1)}^{2}  +  {(y - 7)}^{2}  = 8

EXPLANATION

The given circle has P(-3,5) and Q(1,9) as its diameter.

The center can be obtained using the midpoint rule.

( \frac{ - 3 + 1}{2} , \frac{5 + 9}{2} )

( - 1,7)

The radius is obtained using the distance formula,

r =  \sqrt{( - 1 -  - 3 )^{2}  +  {(7 - 5)}^{2} }

r =  \sqrt{( 2)^{2}  +  {(2)}^{2} }  =  \sqrt{8}

The equation is given by

{(x - h)}^{2}  +  {(y - h)}^{2}  =  {r}^{2}

We substitute the center and radius to get:

{(x -  - 1)}^{2}  +  {(y - 7)}^{2}  =  { (\sqrt{8}) }^{2}

{(x  + 1)}^{2}  +  {(y - 7)}^{2}  = 8

Svetach [21]3 years ago
4 0

Answer:

(x+1)^2+(y-7)^2=8

Step-by-step explanation:

You should try the next one and I can check work or tell you if it is right.  

The diameter length can be found be computing the distance that (-3,5) is to (1,9) which is sqrt(4^2+4^2)=sqrt(32).

The radius is half the diameter so it is sqrt(32)/2.

The center of the circle is the midpoint of a diameter. So compute the (Average of x, average of y)=(-1,7)

So plug into (x-h)^2+(y-k)^2=r^2 we get

(x+1)^2+(y-7)^2=32/4

simplifying gives

(x+1)^2+(y-7)^2=8

(I had to type this twice; my cat jump on my keyboard)

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