If the length of rectangular school hall is 4 times the width and the perimeter be 55m, then the length is 22m and the width of the school hall be 5.5m.
Given that the length of rectangular school hall is 4 times the width.
We are required to find the length and breadth of the rectangle which has the length be 4 times the width.
Perimeter of rectangle is the sum of all the length and breadth of that rectangles.
Perimeter of rectangle is given as 55m
Perimeter=2(L+B)
let the width of rectangle be x.
Length of that rectangle be 4x.
According to question,
2(x+4x)=55
2*5x=55
10x=55
x=55/10
x=5.5 m
Width be 5.5 m.
Length of rectangle be 4*5.5=22m.
Hence if the length of rectangular school hall is 4 times the width then the length is 22m and the width of the school hall be 5.5m.
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Answer:
i think its 2-/+ not sure though sorry
Step-by-step explanation:
Part a:
x + y = 55
y = x + 25
part b:
jackie runs 15 minutes every day.
part c:
it is not possible for jackie to spend 45 minutes a day dancing, since the time she spends dancing and running is 55 minutes, and we know that it takes 15 minutes to run
step-by-step explanation:
let's call and while jackie is dancing
let's call x while jackie is running
then we know that jackie runs and dances for a total of 55 minutes every day
this means that:
x + y = 55
we also know that jackie dances 25 minutes more than she runs.
this meant that:
y = x + 25
now we substitute the second equation in the first and solve for the variable x
x + x + 25 = 552x = 55-252x = 30x = 15
jackie runs 15 minutes every day.
now we find the value of the variable -y
15 + y = 55y = 55-15y = 40
note that it is not possible for jackie to spend 45 minutes a day dancing, since the time she spends dancing and running is 55 minutes, and we know that it takes 15 minutes to run
The cost is $3.75 per gallon. I think that the correct answer for your second question is .307 gallons per dollar.
Answer:
0.2425 or 24.25%
Step-by-step explanation:
If the shipment of 400 components contains 68 defective and, we can estimate the probability of selecting a defective components as
68/400 = 0.17
Now, we have a binomial experiment of 25 trials and we want to compute the probability that more than 5 trials are “success” (defective component)
P(X>5) = 1 - P(X≤ 5)
Since
<em>1 - P(X≤ 5) = 1 - (P(X=0) + P(X=1) + P(X=3) + P(X=4) + P(X=5)</em> =