Answer:
1/5 is a rational number.
Explanation:
Natural numbers are the numbers you use to count with (1, 2, 3, etc.). Nobody uses fractions while counting whole objects unless they think they're funny and want to stall, so 1/5 wouldn't be a rational number.
Whole numbers are the exact same as natural numbers, but with the addition of the number 0 (think about it, no one starts from zero when counting).
Integers include whole numbers as well as their opposites (for example, the opposite of 4 is –4).
As a basic rule of thumb, if the number includes a fraction or a decimal point of any kind, it would be a rational number.
Answer:
The use case diagram is attached.
Explanation:
Create a set of use cases for the following health club membership system:
When members join the health club, they pay a fee for a certain length of time. Most memberships are for one year, but memberships as short as two months are available. Throughout the year, the health club offers a variety of discounts on its regular membership prices (e.g., two memberships for the price of one for Valentine's Day). It is common for members to pay different amounts for the same length of membership. The club wants to mail out reminder letters to members asking them to renew their memberships one month before their memberships expire. Some members have become angry when asked to renew at a much higher rate than their original membership contract, so that the clubwants to track the price paid so that the manager can override the regular prices with special prices when members are asked to renew. The system must track these new prices so that renewals can be processed accurately. One of the problems in the healthclub industry is the high turnover rate of members. While some members remain active for many years, about half of the members do not renew their memberships. This is a major problem because the health club spends a lot in advertising to attract each new member. The manager wants the system to track each time a member comes into the club. The system will then identify the heavy users and generate a report so that the manager can ask them to renew their memberships early, perhaps offering them a reduced rate for early renewal. Likewise, the system should identify members who have not visited the club in more than a month so that the manager can call them and attempt to reinterest them in the club.
The use case diagram is attached.
Answer:
Check the explanation
Explanation:
• We are taking a look at the class B network beginning with 172.0.0.0.0,while Converting this value to binary as:10101100.00010100.00000000.00000000. 32 bits in total, out of this the First 16 bits that are used as network ID and the subsequent 16 bits are used as HostID.Out of the 16 bits that are sued for Network ID the 2 bits namely Bits fifteen and sixteen (15 and 16) have been set and can't be changed and hence only 14 bits are used as network ID.
• Now so that we can divide this network into 50 subnets for class B network we will have to borrow a bit as shown below:
• 10101100.00010100.00000000.00000000=172.0.0.0.0,Adding 1 bit by borrowing from host portion and adding it to network ID will give it 10101100.00010100.00000000.00000000(0 shown in bold) or10101100.00010100.10000000.00000000 (1 shown in bold) will give us 2 unique subnets.i.e changing 1 bit will give us 2 power 1=2 subnets,thus changing 2 bits will give us 2 power 2 subnets =4 similarly changing 6 bits will give us 64 unique subnets.
• Which means and going by the above problem statement in case we need 50 subnets and we also need to change 6 bits in the Network ID to give 50 unique subnets.
• Thus the answer is 6