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Lapatulllka [165]

2 years ago

8

In a set of three lines, a pair of parallel lines is intersected by a transversal. The intersection forms eight special angles.

Two of the special angles, A and B, are corresponding angles.
For the set of parallel lines intersected by a transversal, A=4x and B=-5(x-18).

Part A: Write an equation to represent the corresponding relationship betweenA andB.
Part B: Use the equation to find the measures of A and B.

1 answer:

My name is Ann [436]2 years ago

7 0

Answer:

Part A: 4x = -5(x-18)

Part B: A and B both = 40 degrees

Step-by-step explanation:

Ok, corresponding angles are in the same position on the two parallel lines cut by the transversal. And they are equal in measure. So, upper right = upper right.

So A = B

4x = -5(x -18)

4x = -5x + 90

9x = 90

x = 10

Angle A = 4x = 40 degrees, which means angle B is also 40, but let's show the work:

Angle B = -5(x - 18) = -50 + 90 = 40

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3 years ago

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The particular quadratic solution to the ODE is found as follows:

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3 years ago

1. What are the solutions (coordinate points) to the system of equations?

Leto [7]

Question 1

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${x}^{2} + 5x - 3x + 6 - 6 = 0$

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The solutions are; (0,6) and (-2,0)

Question 2:

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Let us put x=-x,

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We can observe that:

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Question 3:

The given function is

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