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soldi70 [24.7K]
3 years ago
10

Hola necesito eso urgente porfavor lo tengo que entregar en 2 horas

Mathematics
1 answer:
DENIUS [597]3 years ago
6 0
La respuesta es x=10

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What is an equation of the line that passes through the points (-3,8) and (-2,3)?
maw [93]

Answer:

y = -5x + 7

Step-by-step explanation:

You want to find the equation for a line that passes through the two points:

  • (-3,8) and (-2,3)

First of all, remember what the equation of a line is:

  • y = mx+b

Where:

  • m is the slope, and
  • b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

m=\frac{y_{2} -y_{1} }{x_{2} -x_{1} }

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (-3,8), point #1, so the x and y numbers given will be called x₁ and y₁. Or x₁ = -3 and y₁ = 8.

Also, let's call the second point you gave, (-2,3), point #2, so the x and y numbers here will be called x₂ and y₂. Or, x₂ = -2 and y₂ = 3.

Now, just plug the numbers into the formula for m above, like this:

m=\frac{3-8}{-2--3}

or...

m=\frac{-5}{1}

or...

m=-5

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-5x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

  • (-3,8). When x of the line is -3, y of the line <em>must</em> be 8.
  • (-2,3). When x of the line is -2, y of the line <em>must</em> be 3.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=-5x+b. b is what we want, the -5 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,8) and (-2,3).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b <em>for the particular line that passes through the two points you gave!</em>

You can use either (x,y) point you want..the answer will be the same:

  • (-3,8). y=mx+b or 8=-5 × -3+b, or solving for b: b=8-(-5)(-3). b=-7.
  • (-2,3). y=mx+b or 3=-5 × -2+b, or solving for b: b=3-(-5)(-2). b=-7.

See! In both cases we got the same value for b. And this completes our problem.

The equation of the line that passes through the points

(-3,8) and (-2,3)

is

y=-5x-7

7 0
2 years ago
How do you solve this proof? help please. thank you! &lt;3
zubka84 [21]

The answer is given in the file attached

angle addition postulate:

m∠B = m∠1 + m∠3

m∠1 = m∠B - m∠3

3 0
4 years ago
Need help with full explanation first to answer extra points!!!
blsea [12.9K]

Answers:

<h2>1. 35 </h2><h2>2. 12</h2>

Step-by-step explanation:

Those brackets indicate absolute value. Absolute value is the distance of a number from 0 on the number line. In other words, negatives don't matter. There is also no such thing as a negative absolute value.

-2     -1      0      1       2

Both -2 and 2 are the same distance from 0, just in the opposite direction. Both numbers have the same absolute value, which is 2.

Hope This helps. If it did, then....

<em>PLEASE MARK BRAINLIEST</em>

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4 years ago
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Slav-nsk [51]
 That comes out to 3x^2  + 4x - 6 Answer
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So easy it is a telephone

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2 years ago
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