All categories

3 years ago

Describing dilations

Mathematics

1 answer:

s344n2d4d5 [400]3 years ago

7 0

Answer:

dfsdfsfdsddssdf

Step-by-step explanation:

You might be interested in

Solve the quadratic equation x^2-2x-8=0

Dennis_Churaev [7]

Using cross multiplication

$x^{2} -2x-8 =0$
(x-4)(x+2)=0
x-4=0
x+2=0

Thus x=4,-2

7 0

4 years ago

How do we express four less than the square of a number

maksim [4K]

Does this mean how to write it? If so, then it is written:
X= the number
(See picture)

8 0

3 years ago

The two lines, P and Q, are graphed below: Line P is drawn by joining ordered pairs negative 8,15 and 6, negative 12. Line Q is

andreyandreev [35.5K]

Solution:

Keep in mind ,

Equation of line joining two points (a,b) and (p,q) is given by :

$\frac{q-b}{p-a}=\frac{y-b}{x-a}$

Equation of line P which is obtained by joining (- 8,15) and (6, - 12) is given by:

$\frac{y-15}{x+8}=\frac{-12-15}{6+8}\\\\ 14(y-15)=-27(x+8)\\\\ 14 y -210= -27 x - 216\\\\ 27 x+14 y+6=0$

Equation of line Q which is obtained by joining (4,16) and (-9, 10) is given by:

$\frac{y-16}{x-4}=\frac{16-10}{4+9}\\\\ 13(y-16)=6(x-4)\\\\ 13 y -208= 6 x - 24\\\\ 6 x-13 y+184=0$

Equation of line P and Q are

27 x+14 y+6=0-------(1)× 2

6 x-13 y+184=0-------(2)× 9

54 x + 2 8 y+12=0---(1)

54 x -117 y +1656=0----(2)

(1) - (2)

145 y= 1644

y=11.33,

27 x+14 y+6=0-------(1)×13

6 x-13 y+184=0-------(1)×14

351 x + 182 y + 78=0-----(1)

84 x - 182 y +2576=0----(2)

(1) + (2)

435 x + 2654=0

x = - 6.11

So, solution set is (-6.11, 11.33)

Option (C) is true. (−2, 4), because this point makes both the equations incorrect.

8 0

3 years ago

Find the missing dimension of the prism. Round your answer to the nearest hundredth.

Nitella [24]

Answer:

$x = 6.99in$

Step-by-step explanation:

Given

$l =2in$

$Volume = 72.66in^3$

See attachment for prism

Required

Find x

The prism has a regular hexagon base

The base area is calculated as:

$Base\ Area= \frac{3\sqrt 3}{2}l^2$

This gives:

$Base\ Area= \frac{3\sqrt 3}{2} * 2^2$

$Base\ Area= \frac{3\sqrt 3}{2} * 4$

$Base\ Area= 3\sqrt 3 * 2$

$Base\ Area= 6\sqrt 3$

Side x represents the height.

So, we have:

$Volume = Base\ Area*x$

Make x the subject

$x = \frac{Volume }{ Base\ Area}$

$x = \frac{72.66in^3}{6\sqrt 3 in^2}$

$x = \frac{72.66}{6\sqrt 3}in$

$x = \frac{12.11}{\sqrt 3}in$

$x = 6.99in$ --- approximated

6 0

3 years ago

Are <4 and <5 corresponding ?

Mumz [18]

Answer:

what do u mean?

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers