Answer:

Step-by-step explanation:
The two-way frequency table is attached below.
We have to calculate the probability of, a person chosen at random prefers pizza given that they are female, i.e 
This is a conditional probability.
We know that,

So,

From the table,


Putting the values,

It is an acute triangle bc 8 squared + 14 squared is 260 and that is more than 15 squared (225)
Answer:
49/78
Step-by-step explanation:
Probability calculates the likelihood of an event occurring. The likelihood of the event occurring lies between 0 and 1. It is zero if the event does not occur and 1 if the event occurs.
For example, the probability that it would rain on Friday is between o and 1. If it rains, a value of one is attached to the event. If it doesn't a value of zero is attached to the event.
probability that the number on the parking space where she parks is greater than or equal to 30 = numbers greater than or equal to 30 / total numbers
49 / 78
1) 2(6-8x)
2) 4(3-4x)
That seems about right.