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Inga [223]
3 years ago
8

Is c=0.6n an example of a proportional relationship?

Mathematics
1 answer:
stich3 [128]3 years ago
5 0

Yes it is!!!!!!!!!!!!!!!!!!!!!

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Maya is taking her friends to a concert. Each ticket costs $25, and souvenir T-shirts are $12 each. There is a $4 service fee fo
evablogger [386]

Answer:

25x+12y+4 \leq 130

Step-by-step explanation:

Here, x represents the number of tickets and y represents the number of T-shirts.

As per the statement:

Each ticket costs $25,  and souvenir T-shirts are $12 each

⇒Total cost of ticket = 25x and Total cost for T-shirt = 12y

It is also given that there is a $4 service fee for the entire purchase.

25x+12y+4

Since, she has $130

⇒25x+12y+4 \leq 130

Therefore, an inequality could you use to answer the problem is, 25x+12y+4 \leq 130

8 0
3 years ago
Determine the measure of angle BZC.
dusya [7]

Answer:

70 degrees

Step-by-step explanation:

Angle BZA = Angle BZC = 20 degrees

Reason : These two angles are Vertically opposite angles.

Angle BZA + Angle BZC = 90

20 + Angle BZC = 90

Angle BZC = 90 - 20

Angle BZC = 70 degrees

8 0
3 years ago
HELP ASAP!!!!
solong [7]

Answer:

b

Step-by-step explanation:

6 0
4 years ago
11 divided by 15? <br> Help me
OlgaM077 [116]

Answer:

0.733 repeating

Step-by-step explanation:

use your calculator

7 0
2 years ago
For what value of c is the function defined below continuous on (-\infty,\infty)?
kozerog [31]
f(x)= \left \{ {{x^2-c^2,x \ \textless \  4} \atop {cx+20},x \geq 4} \right&#10;

It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
<span>A function, f, is continuous at x = 4 if 
</span><span>\lim_{x \rightarrow 4} \  f(x) = f(4)

</span><span>In notation we write respectively
</span>\lim_{x \rightarrow 4-} f(x) \ \ \ \text{ and } \ \ \ \lim_{x \rightarrow 4+} f(x)

Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
On the other hand, for x < 4, f(x) = x^2 - c^2. Hence 
\lim_{x \rightarrow 4-} f(x) = \lim_{x \rightarrow 4-} (x^2 - c^2) = 16 - c^2

Thus these two limits, the one from above and below are equal if and only if
 4c + 20 = 16 - c²<span> 
 Or in other words, the limit as x --> 4 of f(x) exists if and only if
 4c + 20 = 16 - c</span>²

c^2+4c+4=0&#10;\\(c+2)^2=0&#10;\\c=-2

That is to say, if c = -2, f(x) is continuous at x = 4. 

Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers (-\infty, +\infty)

4 0
3 years ago
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