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3 years ago

Calculate the volume (in mL) of a 2.75 M solution that must be used to make 1.25L of a 0.150 M solution.

Chemistry

2 answers:

Degger [83]3 years ago

8 0

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egoroff_w [7]3 years ago

7 0

Answer:

68mL

Explanation:

Data obtained from the question include :

V1 (volume of original solution) =?

M1 (Molarity of original solution) = 2.75 M

V2 (volume of diluted solution) = 1.25L

M2 (Molarity of diluted solution) = 0.150 M

Using the dilution formula M1V1 = M2V2 , the volume of the original solution can be obtained as follow:

M1V1 = M2V2

2.75 x V1 = 0.15 x 1.25

Divide both side by 2.75

V1 = (0.15 x 1.25)/2.75

V1 = 0.068L

Now let us convert 0.068L to mL in order to obtain the desired result. This is illustrated below:

Recall: 1L = 1000mL

Therefore, 0.068L = 0.068 x 1000 = 68mL

Therefore, the volume of the original solution is 68mL

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Answer:

B. Energy Molecule

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Some SO2 and O2 are mixed together in a flask at 1100 K in such a way ,that at the instant of mixing, their partial pressures ar

kakasveta [241]

Answer:

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Explanation:

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$= 1-2x+0.5-x+2x\\\\= 1+0.5-x\\\\=1.5-x\\$

$\therefore \\\\\to 1.50-x= 1.35 \\\\\to 1.50-1.35= x\\\\\to 0.15= x\\\\ \to x= 0.15\\\\$

calculating the pressure in $So_2$ :

$= (1-2 \times 0.15)$

$= 1-0.30 \\\\ =0.70 \ atm$

calculating the pressure in $O_2$ :

$= (0.5- 0.15)\\\\= 0.35 \ atm \\$

calculating the pressure in $So_3$ :

$= (2 \times 0.15)\\\\= (.30) \ atm \\\\$

Calculating the Kp at 1100 K:

$= \frac{(Pressure(So_3))^2}{(Pressure(So_2))^2 \times Pressure(O_2)}\\\\= \frac{0.30^2}{0.70^2 \times 0.35}\\\\= \frac{0.30 \times 0.30 }{0.70\times 0.70 \times 0.35}\\\\= \frac{0.09 }{0.49\times 0.35} \\\\= \frac{0.09 }{0.1715} \\\\= 0.5247 \ \ or \ \ 0.525 \ \ atm^{-1} \\\\$

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Explanation:

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