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kupik [55]
3 years ago
11

Rolls of foil are 304 mmmm wide and 0.014 mmmm thick. (The density of foil is 2.7 g/cm3g/cm3 .) What maximum length of foil can

be made from 1.06 kgkg of foil?
Chemistry
1 answer:
ratelena [41]3 years ago
3 0

Answer:

92.2 m

Explanation:

Given that:=

The breadth = 304 mm

Height = 0.014 mm

Let Length = x mm

Volume = Length\times breadth\times height

Thus,

Volume = 304\times 0.014\times x\ mm^3=4.256x\ mm^3

Also, 1 mm³ = 0.001 cm³

So, volume = 0.004256 cm³

Given that density = 2.7 g/cm³

Mass = 1.06 kg = 1060 g

So,

Volume=\frac{Mass}{Density}=\frac{1060}{2.7}\ cm^3=392.59\ cm^3

So,

0.004256*x = 392.59

x = 92243.89 mm

Length of foil = 92243.89 mm = 92.2 m

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The element argon is in column 8A and is a noble gas. Nobles gases are completely stable because their outershell is filled with all eight electrons.  Argon has eight valence electrons.

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3 years ago
50 examples word equation with balanced chemical equarion​
gulaghasi [49]
This question may only be ansewered by frequent mattrrs
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To titrate 45.00 milliliters of an unknown HCl sample, use 25.00 milliliters of a standard 0.2000 M NaOH titrant. What is the mo
gtnhenbr [62]
V ( HCl ) = 45.00 mL in liters : 45.00 / 1000 => 0.045 L

M ( HCl ) = ?

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number of moles NaOH :

n = M x V = 0.2000 x 0.025 => 0.005 moles of NaOH

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hope this helps!




4 0
3 years ago
What is the pH of a solution with a H+ ion of 2×10-¹²?​
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Answer:

11.7

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