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scZoUnD [109]
3 years ago
7

The scientific study of matter and the changes it undergoes is called

Chemistry
1 answer:
barxatty [35]3 years ago
5 0
A. Chemistry
The scientific study of matter and the changes it undergoes is called chemistry

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Which of the following is the highest level of organization (least specific)? a. genus c. family b. class d. order
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Hello

Your answer would be:

a. genus
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What is the mass of a sample of water that takes 2000 kJ of energy to boil into steam at 373 K. The latent heat of vaporization
zzz [600]

Answer:

\boxed{\text{889 g}}

Explanation:

The formula relating the mass m of a sample and the heat q to vaporize it is

q = mL, where L is the latent heat of vaporization.

\begin{array}{rcl}2000 \times 10^{3} \text{ J} & = & m \times \dfrac{2.25 \times 10^{6} \text{ J}}{\text{1 kg}}\\\\m & = & \dfrac{2000 \times \times 10^{3}\text{ kg}}{2.25 \times 10^{6}}\\ & = & \text{0.889 kg}\\\\ & = & \text{889 g}\\\end{array}\\\text{The mass of water is $\boxed{\textbf{889 g}}$}

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Given an atom of Mercury (Hg) which has an atomic number of 80 and an atomic mass of 200, what is the total number of particles
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280 is the total number
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A student observes two cells. The student must classify the cells as either fungus or bacteria.What evidence can the student use
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2 years ago
How many moles are contained 80.3 gram of sm(no3)3
swat32
<h3>Answer:</h3>

0.239 mol Sm(NO₃)₃

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 80.3 g Sm(NO₃)₃

[Solve] moles Sm(NO₃)₃

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of Sm - 150.36 g/mol

[PT] Molar Mass of N - 14.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of Sm(NO₃)₃ - 150.36 + 3[14.01 + 3(16.00)] = 336.39 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                 \displaystyle 80.3 \ g \ Sm(NO_3)_3(\frac{1  \ mol \ Sm(NO_3)_3}{336.39 \ g \ Sm(NO_3)_3})
  2. [DA] Divide [Cancel out units]:                                                                        \displaystyle 0.238711 \ mol \ Sm(NO_3)_3

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.238711 mol Sm(NO₃)₃ ≈ 0.239 mol Sm(NO₃)₃

3 0
2 years ago
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