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tamaranim1 [39]
3 years ago
8

Do you notice a pattern in the charge for elements in each group? Explain.

Chemistry
1 answer:
MrRissso [65]3 years ago
7 0

Answer:

Below are some patterns in the charge for elements in each group.

Group 1 elements : 1 valence electron and form ions with charge +1

Group 2 elements : 2 valence electrons and form ions with charge + 2

Group 3 elements : 3 valence electrons and form ions with charge + 3(there are some exceptions as well)

Elements in groups 4 and 5 are unpredictable also the D block elements consist of multiple oxidation states..

Group 6 elements : 6 valence electrons, form ions with charge -2

Group 7 elements: 7 valence electrons, form ions with charge -1  

The octet rule is being followed, the elements form either ionic bond or covalent bond to fulfill it.

eg: when a K atom forms a K+ ion, the ion has the same electron configuration as the noble gas Ar (argon).

When an O atom gains 2 electrons to form the O²⁻ ion, the ion has the same electron configuration as the noble gas Ne (neon).  

Note: Boron (B) is in Group 3 but doesn't form ions.

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Answer: The final pressure inside the tank will be B. 18.05 atm. Gay-Lussac's law is used to predict the changes in pressure or temperature of gases. According to this law, there is a direct relationship between pressure and temperature. As the temperature of gas increases, so, too, will the pressure increase and vice versa.

Further Explanation:

We use the mathematical expression of Gay-Lussac's law to find the final pressure in the tank:

\frac{P_{initial}}{T_{initial}} \ = \frac{P_{final}}{T_{final}}

It is very important to note that when using this equation, all temperatures must be expressed in Kelvin. The conversion from degree Celsius to Kelvin is:

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In the problem, we are given the following information:

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Plugging in these values in the Gay-Lussac Equation, we get:

\frac{23\ atm}{293 \ K} \ = \ \frac{P_{final}}{230\ K}  \\P_{final} \ = \frac{(23 \ atm) \ (230 \ K)}{293 \ K}\\P_{final} \ = \ 18.05 \ atm

The tank was moved from a hotter to a cooler place. At cooler temperatures, gas particles move slower and frequency and strength of their collisions with each other and the wall of the containers decrease. This leads to a decrease in the pressure. Thus, the pressure drops from 23 atm to 18.05 atm when the tank is inside the freezer.

Learn More:

  1. Learn more about Charles' Law brainly.com/question/7259721
  2. Learn more about Ideal Gas Law brainly.com/question/4147359
  3. Learn More about Boyle's Law brainly.com/question/8511562

Keyword: Gas Pressure, Temperature, Gay-Lussac's Law

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