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Hoochie [10]
3 years ago
5

Help plzzzzzzzzzzzzzzzzz

Mathematics
1 answer:
Butoxors [25]3 years ago
4 0

Answer:

6 % is the answer

Step-by-step explanation:

6.50 x 6%=0.39

6.50+0.39=6.89

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Factor the expression 10y+6​
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2(5y+3)

Step-by-step explanation:

10y+6​

Factor out 2

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At a museum shop, Alysa bought two books for $28.50 and some cards for $3.25 each. Her total purchase came to $44.75. How many c
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5

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7 0
3 years ago
A coin is flipped 150 times. The results of the experiment are shown in the following table:
MakcuM [25]
First problem:

The answer is C because theoretically it should have a 50% of landing heads but instead it lands heads 56% of the time. Thus this is 6% higher than 50%. It's not D because there is not specified detail of how the person got this data so you can assume that the person did a fair survey/data collection.

Second problem:

So in a data size of 490, 140 of them we trout. This means that 140/490 or 28.57% of the fish are trout. This means that in a sample size of 5000 fish, 5000*0.2857 or 1428.57 are trout.

Third problem:

The Science students seem to have a higher average score because the average score of Math students are:
(32+33+34+34+35+37+39+40+40)/9=36
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7 0
3 years ago
The heights of North American women are normally distributed with a mean of 64 inches and a standard deviation of 2inches.a. Wha
Charra [1.4K]

Answer:

a)P(X>66)=P(Z>1)=1-P(Z

b)P(\bar X >66)=P(Z>2)=1-P(Z

c) P(\bar X >66)=P(Z>10)=1-P(Z

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

2) Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(64,2)  

Where \mu=64 and \sigma=2

We are interested on this probability

P(X>66)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-\mu}{\sigma})=P(Z>\frac{66-64}{2})=P(Z>1)

And we can find this probability on this way:

P(Z>1)=1-P(Z

3) Part b

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

P(\bar X >66)=P(Z>\frac{66-64}{\frac{2}{\sqrt{4}}}=2)

And using a calculator, excel or the normal standard table we have that:

P(Z>2)=1-P(Z

4) Part c

P(\bar X >66)=P(Z>\frac{66-64}{\frac{2}{\sqrt{100}}}=10)

And using a calculator, excel or the normal standard table we have that:

P(Z>10)=1-P(Z

3 0
3 years ago
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