That is the slope at f(1)
one way is to just take the derivitive
f'(x)=2x+(1/x)
for ti-89, do calc then derivitive then input "x^2+ln(x),x)" and click enter to get the derivitive
you would get f'(x)=2x+(1/x)
an easier way would be to have
click calc then differntiate then type x^2+ln(x),x)|x=1 then click enter
you get f'(1)=3
answer is 3
Answer:
Well yes. So we know that our x intercepts are -2 and postive 3. If we look at the graph, we can see that when y=0, the quadratic is at both -2 and 3 for x.
Step-by-step explanation:
This might not be the full reason why this is the answer, but this is for sure part of why the factored form is correct
Sorry I cannot help more than that! :(
1. z-9 2. 9+z 3. I THINK 9/z 4. 9z
I haven't done proofs in a while, but one thing that might help is that only if two lines were parallel would angles 3 and 1 be congruent (3 is congruent to 2, which is congruent to 1, so they're all congruent to each other).
Answer:
286.94 cm
Step-by-step explanation:
Data:
Area = 8,607
b1 = 105
b2 = 123
Area = 1/2 * (b1 + b2) * h
h = 2 * Area/b1 + b2
h = 2 * 8,607/105 + 123
h = 286.94 cm
I'm not sure if it's right but that's what my calculator gave me.
