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Sergio [31]
3 years ago
15

Triangle C F E is shown. Angle C F E is a right angle. An altitude is drawn from point F to point D on side C E, forming a right

angle. The length of F D is 9, the length of C D is 5, and the length of D E is 2 x + 3.
What is the value of x and the length of segment DE?
Mathematics
2 answers:
IrinaVladis [17]3 years ago
7 0

Answer:6.6

and 16.2

Step-by-step explanation:

beks73 [17]3 years ago
3 0

Answer:hard to do without a pic

is there a pic of the triangle

Step-by-step explanation:

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Answer:

12

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3 years ago
(5j − 2q) − (− 4 + 3j − 6q) PLEASE I WILL GIVE YOU 15 POINTS
Step2247 [10]

Answer: 2j + 4q + 4

Distribute the Negative Sign:

=5j−2q+−1(−4+3j−6q)

=5j+−2q+(−1)(−4)+−1(3j)+−1(−6q)

=5j+−2q+4+−3j+6q

Combine Like Terms:

=5j+−2q+4+−3j+6q

=(5j+−3j)+(−2q+6q)+(4)

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3 years ago
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Here is a diagram of a person standing next to a tree.
Vlad [161]
The person is half of the trees length so the answer would be
1.75* 2= 3.5
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An object is launched directly in the air at a speed of 64 feet per second from a platform located 16 feet above the ground. The
zloy xaker [14]

Considering the vertex of the quadratic equation, the maximum height that the object will reach is of 80 feet.

<h3>What is the vertex of a quadratic equation?</h3>

A quadratic equation is modeled by:

y = ax^2 + bx + c

The vertex is given by:

(x_v, y_v)

In which:

  • x_v = -\frac{b}{2a}
  • y_v = -\frac{b^2 - 4ac}{4a}

Considering the coefficient a, we have that:

  • If a < 0, the vertex is a maximum point.
  • If a > 0, the vertex is a minimum point.

In this problem, the equation is:

f(t) = -16t² + 64t + 16.

Hence the coefficients are:

a = -16, b = 64, c = 16.

The maximum value is found as follows:

y_v = -\frac{64^2 - 4(-16)(16)}{4(-16)} = 80

More can be learned about the vertex of a quadratic equation at brainly.com/question/24737967

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2 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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