One step is to right click on the word to add it to her personal dictionary. or, <span><span>Press F7. Word starts the spelling and grammar checking utility. </span><span>Make corrections, as appropriate, when prompted.
</span></span>
However, one can create a macro that would do the conversions :
1) Identify a list of words whose spelling you want to convert.2) Turn on the macro recorder. 3) Use the Replace feature to replace the spellings.4) Turn off the macro recorder.
The macro will do a conversion from one to the other. Later, as we have more words that need to be automatically replaced, we can just edit the macro and add those words.
Answer:
couple.py
def couple(s1,s2):
newlist = []
for i in range(len(s1)):
newlist.append([s1[i],s2[i]])
return newlist
s1=[1,2,3]
s2=[4,5,6]
print(couple(s1,s2))
enum.py
def couple(s1,s2):
newlist = []
for i in range(len(s1)):
newlist.append([s1[i],s2[i]])
return newlist
def enumerate(s,start=0):
number_Array=[ i for i in range(start,start+len(s))]
return couple(number_Array,s)
s=[6,1,'a']
print(enumerate(s))
print(enumerate('five',5))
Explanation:
Answer:
// code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;
int largest=INT_MIN;
int smallest=INT_MAX;
int n;
cout<<"Enter 10 Integers:";
// read 10 Integers
for(int a=0;a<10;a++)
{
cin>>n;
// find largest
if(n>largest)
largest=n;
// find smallest
if(n<smallest)
smallest=n;
// if input is even
if(n%2==0)
{
// sum of even
sum_even+=n;
// even count
eve_count++;
}
else
{
// sum of odd
sum_odd+=n;
// odd count
odd_count++;
}
}
// print sum of even
cout<<"Sum of all even numbers is: "<<sum_even<<endl;
// print sum of odd
cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;
// print largest
cout<<"largest Integer is: "<<largest<<endl;
// print smallest
cout<<"smallest Integer is: "<<smallest<<endl;
// print even count
cout<<"count of even number is: "<<eve_count<<endl;
// print odd cout
cout<<"count of odd number is: "<<odd_count<<endl;
return 0;
}
Explanation:
Read an integer from user.If the input is greater that largest then update the largest.If the input is smaller than smallest then update the smallest.Then check if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.
Output:
Enter 10 Integers:1 3 4 2 10 11 12 44 5 20
Sum of all even numbers is: 92
Sum of all odd numbers is: 20
largest Integer is: 44
smallest Integer is: 1
count of even number is: 6
count of odd number is: 4
B. Extract all files
In order to access a zipped (compressed) folder you have to extract them. The prompt should say “Extract” not Unzip.
