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Alinara [238K]
3 years ago
8

Simplify cos omega tan omega

Mathematics
1 answer:
Nana76 [90]3 years ago
3 0

Answer:

B) sin Ф

Step-by-step explanation:

Use the pythagorean identity for cos and tan

tan  = \frac{sin}{cos }     Multiply both sides by cos

sin Ф = sin Ф

If this answer is correct, please make me Brainliest!

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2,2,and2 because there are 2 sides of a coin, 2 cards, and 2 marbles
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2 years ago
3 1/4% of 800?<br><br><br> Please help
asambeis [7]
The answer for this problem is 26.
7 0
2 years ago
Read 2 more answers
You Are Planting a garden in the shape of an equilateral triangle as shown in the diagram. You want to find the area of the gard
S_A_V [24]

Answer:

Area of the garden = 16\sqrt{3} ft²

Step-by-step explanation:

Given:

Base of garden = 8 Ft

Find:

Area of the garden = ?

First, we have to find height of the triangle.

Height = \sqrt{8^2-4^2}\\\\Height = \sqrt{64-16}\\\\Height = \sqrt{48}\\\\Height = 4\sqrt{3}\\

Computation of area of the garden:

Area of the garden = 1/2 × b × h

Area of the garden = 1/2 × 8 × 4\sqrt{3}

Area of the garden = 16\sqrt{3} ft²

4 0
3 years ago
The angles of a triangle add up to 180 degrees. The second angle is 30 degrees larger than the smallest angle. The third angle i
Rudik [331]

Answer:

50

Step-by-step explanation:

first angle = x

second angle = x+30

third angle = 4x

x + (x+30) + 4x = 180

6x + 30 = 180

6x = 180 - 30

6x = 150

x = 150:6

x = 50

3 0
3 years ago
During her 8th week of training a woman ran 20 total miles,during her 13th week of training she ran 33 total miles.
allochka39001 [22]
So 8th week:20
13th week:33
13-8=5
33-20=13
grouth of 13 per 5 weeks or about 2.6 increse per week

so if she ran 37 miles then
37-33=4
so an increse of 4 or about 1.5 more weeks soweek 14.5

another way is to find the ratio of miles to weeks
20/8=2.5
33/13=2.54
average 2.5 and 2.54 and get 2.52
37/x=2.52
solve for x
37/x=2.52
multiply both sides by x
37=2.52x
divide both sides by 2.52
14.68=x
she is on her 14.68 week
you might want to round up

4 0
3 years ago
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