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Naya [18.7K]
3 years ago
5

A line passes through the point (0, 1) and has a positive slope. Which of these points could that line NOT pass through? Check a

ll that apply.
(12, 3)
(–2, –5)
(–3, 1)
(1, 15)
(5, –2)





answer is
c,e
Mathematics
2 answers:
QveST [7]3 years ago
6 0

Answer: (–3, 1) , (5, –2)

Step-by-step explanation: Got it right Edgenuity

KengaRu [80]3 years ago
3 0

Answer:

C AND E IS THE RIGHT ANSWERS

Step-by-step explanation:

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32600÷9330?<br>Please answer:(​
forsale [732]

Answer:

3.49410504

It is the answer hope it helps.

Mark me as Brainliest plz

3 0
3 years ago
Read 2 more answers
Você é um comandante de uma espaçonave. Sua missão é chegar até Alfa Centauro em cinco anos. A distância do Sol até Alfa Centaur
Deffense [45]

Answer:

The spaceship will get to Alpha Centaur in time

Step-by-step explanation:

<u><em>The complete question in English is</em></u>

You're the commander of a spaceship. Your mission is to reach Alpha Centaur  in five years. The distance from the sun to Alpha Centaur is 2.5 x 10^13 miles. The distance  from Earth to Sun is approximately 9.3 x 10^7

miles. Your spaceship can travel  at the speed of light. You know that light can travel a distance of 5.88 x 10^12  miles in a year. Can you get to Alpha Centaur in time?

step 1

Find the time it takes for the spaceship to travel from Earth to the Sun

The distance from the Earth to Sun is equal to

9.3*10^7\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{9.3*10^7\ miles}{x}\\\\x=(9.3*10^7)/5.88*10^{12}\\\\x=1.58*10^{-5} \ years

This time is very small in years

Convert to minutes

1.58*10^{-5} \ years=1.58*10^{-5} (365)(24)(60)=8.3\ min

step 2

Find the time it takes for the spaceship to travel from the Sun to Alpha Centaur

The distance from the the Sun to Alpha Centaur is equal to

2.5*10^{13}\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{2.5*10^{13}\ miles}{x}\\\\x=(2.5*10^{13})/5.88*10^{12}\\\\x=4.25\ years

4.25\ years< 5\ years

therefore

The spaceship will get to Alpha Centaur in time

3 0
2 years ago
Jane paid $35 for her meal. If the cost of the meal was $30, what was the tax rate.
uranmaximum [27]

Answer:

15% tax

Step-by-step explanation:

7 0
2 years ago
Please help me with the problems in my picture
Tamiku [17]

Answer:

1.) C

2.) miles

3.) Car A is faster

3 0
2 years ago
The area of a regular octagon is 35 cm 2 what is the area of a regular octagon with sides three times as large
Maurinko [17]
The area of a polygon = n*side^2 / (4 * tan(180/n))
where "n" is the number of sides

Let's calculate area for side = 2
area = 8*2^2 / (4 * tan(180/8))
area = 32 / (4 * tan(22.5))
area = 32 / 4*0.41421
<span> <span> <span> area = 19.3138746047 </span> </span> </span>

Now, let's calculate area for side = 6
area = 8*6^2 / (4 * tan(180/8))
area = 288 / <span> <span> <span> 1.65684 </span> </span> </span>
area = <span> <span> <span> 173.824871442 </span> </span> </span>

<span> <span> 173.824871442 </span> / </span><span><span>19.3138746047 = </span> 9

So, the area would be 9 times larger.

ALSO, looking at the formula
</span>n*side^2 / (4 * tan(180/n))
we can see that the side length appears just once in the formula and we are to square it in the calculation.  So, if we increase the side length is increased by 3, then the area increases by 3^2 or 9.


5 0
3 years ago
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