Given:
t1 = 3.6 h
t2 = 4.5 h
x = speed of boat
y = speed of water
Required:
a) Expression of distance traveled with moving water with 3.6h
Expression of distance traveled with moving water with 4.5h
b) Solve for y
c) Percent of boat's speed is the water current
Solution:
Working formula: distance = velocity*time
a) For travelling downstream, we get the equation
d = (x +y)*3.6
For travelling upstream, we get the equation
d = (x-y)*4.5
b) Setting the distance as equal for travelling upstream or downstream, we arrive at the equation of
(x+y)*3.6 = (x-y)*4.5
3.6x + 3.6y = 4.5x - 4.5y
8.1y =0.9x
y = x/9
c) percentage = 1/9*100% = 11.1%
<em>ANSWERS: a) d = (x+y)*36; d = (x-y)*4.5
</em> <em>b) y = x/9
</em> <em>c) 11.1%</em>
Answer:
2 units up for every one unit across, or just simply 2
Step-by-step explanation:
Analytically, it will be
-√(1+1²) = -√2
The calculator shows it to be -1.41421356237
_____
= -√2 to 12 significant digits.
Answer: 40x^2+8x
Step-by-step explanation:
First, distribute the 4 with the 10x^2 = 40x^2
Second distribute the 4 with the 2x = 8x
Third put them together: 40x^2+8x
