Ask question

Ask question

All categories

2 years ago

9

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!

1 answer:

svet-max [94.6K]2 years ago

4 0

Answer:

tan (C) = 2.05

Step-by-step explanation:

Given:

A right angled triangle CDE right angled at ∠D.

Side CD = 39

Side DE = 80

Side CE = 89

We know, from trigonometric ratios that, the tangent of any angle is equal to the ratio of the opposite side to the angle and the adjacent side of the angle.

Therefore, tangent of angle C is given as:

$\tan(\angle C)=\frac{DE}{CD}$

Plug in the given values and solve for angle C.This gives,

$\tan(\angle C)=\frac{80}{39}\\\\\tan(\angle C)=2.051\approx 2.05(Rounded\ to\ nearest\ hundredth)$

Therefore, the measure of tangent of angle C is 2.05.

You might be interested in

How to remember what I have learnt

kati45 [8]

A way to remember what you have learned is creating notes or doing practice problems

7 0

2 years ago

Read 2 more answers

If 60% of the students in the classroom have a pet at home. If 15 students have a pet, what is the total number of students in t

torisob [31]

There are 25 students in the classroom

3 0

2 years ago

If line segment BC is considered the base of triangle ABC, what is the corresponding height of the triangle?

Leni [432]

Answer:

1.6 units

Step-by-step explanation:

Coordinates of A : (-1,1)

Coordinates of B : (3,2)

Coordinates of C :( -1,-1)

Now to find the length of the sides of the triangle we will use distance formula :

$d =\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

To find length of AB

A = $(x_1,y_1)=(-1,1)$

B= $(x_2,y_2)=(3,2)$

Now substitute the values in the formula:

$d =\sqrt{(3-(-1))^2+(2-1)^2}$

$d =\sqrt{(4)^2+(1)^2}$

$d =\sqrt{16+1}$

$d =\sqrt{17}$

$d =4.12$

Now to find length of BC

B= $(x_1,y_1)=(3,2)$

C = $(x_2,y_2)=(-1,-1)$

Now substitute the values in the formula:

$d =\sqrt{(-1-3)^2+(-1-2)^2}$

$d =\sqrt{(-4)^2+(-3)^2}$

$d =\sqrt{16+9}$

$d =\sqrt{25}$

$d =5$

Now to find length of AC

A = $(x_1,y_1)=(-1,1)$

C = $(x_2,y_2)=(-1,-1)$

Now substitute the values in the formula:

$d =\sqrt{(-1-(-1))^2+(-1-1)^2}$

$d =\sqrt{(0)^2+(-2)^2}$

$d =\sqrt{4}$

$d =2$

Thus the sides of triangle are of length 4.12, 5 and 2

Now to find area of triangle we will use heron's formula :

To calculate the area of given triangle we will use the heron's formula :

$Area = \sqrt{s(s-a)(s-b)(s-c)}$

Where $s = \frac{a+b+c}{2}$

a,b,c are the side lengths of triangle

a = 4.12

b=5

c=2

Substitute the values

Now substitute the values :

$s = \frac{4.12+5+2}{2}$

$s =5.56$

$Area = \sqrt{5.56(5.56-4.12)(5.56-5)(5.56-2)}$

$Area = 3.99$

Now to find the height of altitude corresponding to side BC

So, formula of area of triangle $=\frac{1}{2} \times Base \times Height$

Since Area = 3.99 square units

So, $3.99 =\frac{1}{2} \times BC \times Height$

So, $3.99 =\frac{1}{2} \times 5\times Height$

$3.99 =2.5 \times Height$

$\frac{3.99}{2.5}=Height$

$1.596=Height$

Thus the altitude corresponding to the BC is of length 1.596 unit ≈ 1.6 units

Thus Option D is correct.

7 0

2 years ago

Read 2 more answers

Rachel and David were shopping for holiday gifts when they noticed a Thanksgiving sweater on the discount rack. Rachel really wa

Leona [35]

Answer:

$Sales\ Price = \$9.60$

Step-by-step explanation:

Given

$Price = \$24.00$

$Discount = 60\%$

Required

Determine the sales price

First, we calculate the discount price

$Discount\ Price = Price * Discount$

$Discount\ Price = \$24.00 * 60\%$

$Discount\ Price = \$14.4$

The sales price is then calculated by subtracting the discount price from the original price of the item

$Sales\ Price = Price - Discount\ Price$

$Sales\ Price = \$24.00 - \$14.40$

$Sales\ Price = \$9.60$

8 0

2 years ago

Need help please<br> thanks

eduard

Atoms best in life esfff

3 0

2 years ago