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3 years ago

Plzzzzz helpppp i will give brainliestttttt

Mathematics

2 answers:

Rus_ich [418]3 years ago

4 0

Answer:

Fourth (last) rectangle has an area of 18 square units

Step-by-step explanation:

$l = 1 - ( - 5) = 1 + 5 = 6 \: units \\ w = 1 - ( - 2) = 1 + 2 = 3 \: units \\ area = lw = 6 \times 3 = 18 \: {units}^{2} \\$

erik [133]3 years ago

3 0

Answer:

The fourth rectangle.

Step-by-step explanation:

The first rectangle has one side with length 1-(-1)=2 units, and another side with length 3-(-3)=6 units. Multiplying these two side lengths together, you get a total area of 12 units squared. For the second rectangle, it has one side length of 2 units and another of 7 units, which is a total area of 14 units squared. For the third rectangle, it has one side with length 4 units and another side with length 5 units, which is a total area of 20 units. This leaves us with the last rectangle, which has side lengths of 3 and 6 units. 3*6=18, meaning that the fourth rectangle is the one with an area of 18. Hope this helps!

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A food processor packages orange juice in small jars. The weights of the filled jars are approximately normally distributed with

Ratling [72]

Answer:

$P(X>10.983)=P(\frac{X-\mu}{\sigma}>\frac{10.983-\mu}{\sigma})=P(Z>\frac{10.983-10.5}{0.3})=P(z>1.61)$

And we can find this probability using the complement rule and with excel or the normal standard table:

$P(z>1.61)=1-P(z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(10.5,0.3)$

Where $\mu=10.5$ and $\sigma=0.3$

We are interested on this probability

$P(X>10.983)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>10.983)=P(\frac{X-\mu}{\sigma}>\frac{10.983-\mu}{\sigma})=P(Z>\frac{10.983-10.5}{0.3})=P(z>1.61)$

And we can find this probability using the complement rule and with excel or the normal standard table:

$P(z>1.61)=1-P(z$

8 0

3 years ago

Please help for eleven points

Arlecino [84]

C: B:

3 0

6 9

9 18

12 27

All you had to do was plug in the value for c or b and solve. You can tell this is most likely correct because you see patterns for both variables. C is going up by threes, while b is going up by nines.

3 0

3 years ago

PLZZZZZZ I NEED HELP IM SO TIRED PLZZZZZZZZ

ipn [44]

Answer:

$8.99$