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vlabodo [156]
4 years ago
12

What is 3+3×3-3+3 equal?

Mathematics
2 answers:
tangare [24]4 years ago
5 0
Use Pemdas it would be much easier to do that
LiRa [457]4 years ago
4 0
12
Remember to use PEMDAS when solving these problems. You multiply before you work with addition and subtraction.
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I just need points xD 12.512
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3 years ago
Find the zeros of each function by using a graph and a table f(x)=x^2+3x-18.
Debora [2.8K]

1) Finding the zeros of this function f(x) =x² +3x -18

f(x) = x²+3x-18 <em>Factoring this equation, and rewriting it</em>

<em />

<em>Which two numbers whose sum is equal to 3 and their product is equal to 18?</em>

<em>6 -3 = 3 and 6 *-3 = -18</em>

<em />

<em>So we can rewrite as (x +6) (x-3)</em>

<em> </em>

(x+6)(x-3)=0 <em>Applying the Zero product rule, to find the roots</em>

x+6=0,

x=-6

x-3=0,

x=3

S={3,-6}

2) Setting a table, plugging in the values of x into the factored form: (x-6)(x-3)

x | y |

1 | -14 (1 +6)(1-3) =-14

2 | -8 (2 +6)(2-3) =-8

3 | 0

4 | 10

-5 | -8

-6 | 0

3) Plotting the function:

5 0
1 year ago
Loren drove 200 miles at a certain rate, and his wife, Lois, drove 100 miles at a rate 10 mph slower. If Loren had driven for th
NeX [460]

As long as Loren drove, the law of motion was

200 = st_1 \implies t_1 = \dfrac{200}{s}

As long as Loid drove, the law of motion was

100 = (s-10)t_2 \implies t_2 = \dfrac{100}{s-10}

So, the total time they took is

t_1+t_2=\dfrac{200}{s}+\dfrac{100}{s-10}

Had Loren driven the whole time, the law of motion would have been

300=st_3 \implies t_3 = \dfrac{300}{s}

And we know that this time would have been 30 minutes (i.e. 0.5 hours) faster. So, we have

t_3 = t_1+t_2-0.5

This translates into

\dfrac{300}{s}=\dfrac{200}{s}+\dfrac{100}{s-10}-\dfrac{1}{2}

If we subtract 200/s from both sides, we have

\dfrac{100}{s}=\dfrac{100}{s-10}-\dfrac{1}{2}

We can simplify the right hand side by summing the two fractions:

\dfrac{100}{s-10}-\dfrac{1}{2} = \dfrac{200-(s-10)}{2(s-10)}=\dfrac{210-s}{2(s-10)}

So, we have to solve

\dfrac{100}{s}=\dfrac{210-s}{2(s-10)}

If we cross multiply the denominators, we have

200(s-10)=s(210-s) \iff 200s-2000=210s-s^2 \iff s^2-10s-2000=0

Which yields the solutions

s=-40,\quad s=50

We accept the positive solution, because the negative would mean to travel backwards, so Loren's rate was 50mph

5 0
3 years ago
Read 2 more answers
Patrick can learn 42 blessings in 6 hours. At that rate, how many blessings can he learn in 9 hours?
Vladimir [108]

divide 42 by 6 and get 7 so mulyiply 7 by 9

8 0
2 years ago
I need help asap like nowwwwwwwww
Allisa [31]

A.)  Both services will cost the same if it is for a 3 hours service.

B.) 16+9X=20+7X.

=>9x-7x=20-16.

=>2x=4.

=>x=4/2.

=>x= 2.

3 0
3 years ago
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