All categories

3 years ago

What is 3+3×3-3+3 equal?

Mathematics

2 answers:

tangare [24]3 years ago

5 0

Use Pemdas it would be much easier to do that

LiRa [457]3 years ago

4 0

12
Remember to use PEMDAS when solving these problems. You multiply before you work with addition and subtraction.

You might be interested in

Write this as an equation, then solve.

ANTONII [103]

19.5 in difference
difference indicates that you'll be subtracting so 29 3/4 - 10 1/4 = 19.5

3 0

3 years ago

The hypotenuse AB of the right triangle ABC is parallel to the axis of the abscess. Find the length of the hypotenuse if A (-1;

lukranit [14]

Answer:

10.25

Step-by-step explanation:

The slope of AC is given by the slope formula:

m = (y2 -y1)/(x2 -x1)

m = (-4 -1)/(3 -(-1)) = -5/4

Then the slope of CB is the opposite reciprocal, 4/5. The equation of line CB in point-slope form is ...

y -k = m(x -h) . . . . . . line with slope m through point (h, k)

y -(-4) = 4/5(x -3) . . . . line CB

When y = 1 (to match the y-value of A), then ...

1 +4 = 4/5(x -3)

5(5/4) = (x -3) . . . . . multiply by 5/4

6.25 +3 = x = 9.25 . . . . add 3

Point B is (9.25, 1).

The length of the hypotenuse is ...

9.25 -(-1) = 10.25

6 0

2 years ago

NEED HELP! Thanks!

sladkih [1.3K]

I think the answer would be 7.5 hours or 4 hours,not so sure which one exactly

6 0

3 years ago

What is a histogram?

aliya0001 [1]

Answer:

a diagram consisting of rectangles whose area is proportional to the frequency of a variable and whose width is equal to the class interval.

explanation: A histogram is a chart that shows frequencies for. intervals of values of a metric variable. Such intervals as known as “bins” and they all have the same widths. The example above uses $25 as its bin width. So it shows how many people make between $800 and $825, $825 and $850 and so on.

5 0

3 years ago

Solve the initial value problem where y′′+4y′−21 y=0, y(1)=1, y′(1)=0 . Use t as the independent variable.

igor_vitrenko [27]

Answer:

$y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}$

Step-by-step explanation:

y′′ + 4y′ − 21y = 0

The auxiliary equation is given by

m² + 4m - 21 = 0

We solve this using the quadratic formula. So

$m = \frac{-4 +/- \sqrt{4^{2} - 4 X 1 X (-21))} }{2 X 1}\\ = \frac{-4 +/- \sqrt{16 + 84} }{2}\\= \frac{-4 +/- \sqrt{100} }{2}\\= \frac{-4 +/- 10 }{2}\\= -2 +/- 5\\= -2 + 5 or -2 -5\\= 3 or -7$