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Pavel [41]
1 year ago
13

Find the zeros of each function by using a graph and a table f(x)=x^2+3x-18.

Mathematics
1 answer:
Debora [2.8K]1 year ago
5 0

1) Finding the zeros of this function f(x) =x² +3x -18

f(x) = x²+3x-18 <em>Factoring this equation, and rewriting it</em>

<em />

<em>Which two numbers whose sum is equal to 3 and their product is equal to 18?</em>

<em>6 -3 = 3 and 6 *-3 = -18</em>

<em />

<em>So we can rewrite as (x +6) (x-3)</em>

<em> </em>

(x+6)(x-3)=0 <em>Applying the Zero product rule, to find the roots</em>

x+6=0,

x=-6

x-3=0,

x=3

S={3,-6}

2) Setting a table, plugging in the values of x into the factored form: (x-6)(x-3)

x | y |

1 | -14 (1 +6)(1-3) =-14

2 | -8 (2 +6)(2-3) =-8

3 | 0

4 | 10

-5 | -8

-6 | 0

3) Plotting the function:

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evablogger [386]

Answer:

5/6 w

Step-by-step explanation:

reorder the terms ( use the commuative property)

5/6 w

so the answer is 5/6 w

7 0
3 years ago
Will report anybody who gives a link!<br><br> 3,947 ÷ 45 = (?) R (?)
Free_Kalibri [48]

Answer:

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8 0
3 years ago
Prove cos a = 5/13 pls solve it and no link pls..........​
Scorpion4ik [409]

<u>Answer</u> : The demonstration is below :)

Step-by-step explanation :

<u>We use Pythagoras' </u><u>theorem </u><u>:</u>

  • In the triangle ABC we have :

AB² = AC² - BC² = 15² - 9² = 144 = 12²

  • In the triangle ABD we have :

DB² = AD² - AB² = 13² - 12² = 5²

cos(a) = BD/AD = 5/13

3 0
2 years ago
A cell phone company charges $55 per month for unlimited minutes plus $0.25 per text sent. If the charges to Dayne's cell phone
Svetach [21]
A: 180
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7 0
3 years ago
Read 2 more answers
Divide. Write the quotient in lowest terms. 3 3/4 ÷ 5/7
olchik [2.2K]

Rewrite 3 3/4 as an improper fraction

3 3/4 = 15/4

Now you have

15/5 / 5/7

When you divide fractions, change the division to multiplication and flip the second fraction over:

15/4 x 7/5

Now multiply the top numbers together and the bottom numbers together:

( 15 x 7) / (4 x 5) = 105/20

Write as a proper fraction:

105/20 = 5 1/4

5 0
3 years ago
Read 2 more answers
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