$r(t)=(\cos{t},\sin{t},t)
\\r'(t)=(-\sin{t},\cos{t},1)
\\t= \frac{3\pi}{6} = \frac{\pi}{2}
\\ r'(t)=(-\sin{\frac{\pi}{2}},\cos{\frac{\pi}{2}},1)
\\ r'(t)=(-1,0,1)
\\
\\x=0+t(-1)=-t
\\y=1+t\times 0=1
\\z= \frac{\pi}{2} +t$

5 0

3 years ago

Please help me with this question!!

Bess [88]

Answer:

$x=16 * cos(46)$

Step-by-step explanation:

Well, first let's look at our trig identities. We can set up a cosine function using the given angle:

$cos (46^{o} ) = \frac{x}{16}$ (adjacent/hypotenuse)

Then, multiplying both sides by 16 gives us:

$x=16 * cos(46)$

Hope this helps!

4 0

3 years ago

Write this expression in radical form

Lerok [7]

It is already in radical form......... but, if you want us to make it into exponential form, it is 8x^(2/3)

3 0

3 years ago

Write .125 as a fraction reduced to lowest terms.

VMariaS [17]

Answer:

1/8

Step-by-step explanation:

Hope this helps you! <33

7 0

3 years ago

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