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timama [110]
4 years ago
15

How do i solve x^2+7x=3x

Mathematics
2 answers:
valina [46]4 years ago
7 0
To solve, you must make one side of the equation equal to zero. We can do this by subtracting 3x on both sides of the equation.

<span>x^2 + 7x = 3x
</span>       - 3x    -3x

x^2 + 4x = 0.

Then we substitute the equation into the quadratic equation.

\frac{-b+- \sqrt{b^2-4ac} }{2a}

Where a = 1 b = 4 and c = 0

\frac{-(4)+- \sqrt{(4)^2-4(1)(0)} }{2(1)}

We first solve whats inside the square root.

\frac{-(4)+- \sqrt{16} }{2(1)}

\sqrt{16} = 4

Now we solve for -4 and 4.

-4 - 4 = -8
-4+4=0

Then divide both answer by 2

\frac{-8}{2} = -4
The division of any by zero is zero

So the answer are x = -4 and x = 0
saveliy_v [14]4 years ago
5 0
X^2 + 7x - 3x = 0
Simplify x^2 + 7x - 3x to x^2 + 4x
X^2 + 4x = 0
Factor out the common term x
X ( x + 4 ) = 0
Solve for x
X = 0,-4
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Answer:

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9v/ 9 = 841 /9 - 16b/9

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6728/9 -83/9

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