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IrinaK [193]
3 years ago
12

(−5.2)+(−3.8)–{(−1.2)–[(−0.5)–(−0.7)]}

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
3 0

(−5.2)+(−3.8)–{(−1.2)–[(−0.5)–(−0.7)]}

To simplify this problem we will use order of operations. PEMDAS which stands for Parenthesis Exponent Multiplication Division Addition Subtraction

=(−5.2)+(−3.8)–{(−1.2)–[(−0.5)+0.7]}

=(−5.2)+(−3.8)–{(−1.2)–[−0.5+0.7]}

=(−5.2)+(−3.8)–{(−1.2)–[0.2]}

=(−5.2)+(−3.8)–{(−1.2)–0.2}

=(−5.2)+(−3.8)–{−1.2–0.2}

=(−5.2)+(−3.8)–{-1.4}

=(−5.2)+(−3.8)+1.4

=(−5.2)−3.8+1.4

=(−5.2)-2.4

=−5.2-2.4

=-7.6


Hence final answer is -7.6.

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Hezekiel runs 1000 m at a rateof 3 minutes per km. how long does he take to run 500 m​
lana66690 [7]

Step-by-step explanation:

1 km = 1000 m

(hence the term "kilo" which means 1000).

so. he runs 1000 m at the rate of 3 minutes per km, that means 3 minutes per 1000 m.

now, we can see the solution already with our eyes.

but let's do it formally :

the rate or ratio between time and distance must be the same for the same speed.

so,

3 min / 1000 m = x min / 500 m

500 m × 3 min / 1000 m = x min

1/2 × 3 min = x min

3/2 = 1.5 min = x min

so, it takes him 1.5 minutes (90 seconds) to run 500 m.

3 0
2 years ago
Given the function f(x) = 6x^2 −13, what is f(-3)?
Naya [18.7K]
<h3>Answer: 41</h3>

Work Shown:

f(x) = 6x^2 - 13

f(x) = 6(x)^2 - 13

f(-3) = 6(-3)^2 - 13 ... replace every x with -3; use PEMDAS to simplify

f(-3) = 6(9) - 13

f(-3) = 54 - 13

f(-3) = 41

7 0
3 years ago
Solve for x. 3x ^2 -4 = 8
LenKa [72]

Answer:

x = ±2

Step-by-step explanation:

3x ^2 -4 = 8

Add 4 to each side

3x ^2 -4+4 = 8+4

3x^2 =12

Divide each side by 3

3x^2 =12

3x^2/3 = 12/3

x^2 = 4

Take the square root of each side

sqrt(x^2) = ±sqrt(4)

x = ±2

5 0
3 years ago
Read 2 more answers
What is the local minimum value of the function? (Round answer to the nearest hundredth) g(x)=x^4-5x^2+4
Serhud [2]
The local minimum of function is an argument x for which the first derivative of function g(x) is equal to zero, so:
g'(x)=0
g'(x)=(x^4-5x^2+4)'=4x^3-10x=0
x(4x^2-10)=0
x=0 or 4x^2-10=0
4x^2-10=0 /4
x^2-10/4=0
x^2-5/2=0
[x-sqrt(5/2)][x+sqrt(5/2)]=0

Now we have to check wchich argument gives the minimum value from x=0, x=sqrt(5/2) and x=-sqrt(5/2).
g(0)=4
g(sqrt(5/2))=25/4-5*5/2+4=4-25/4=-9/4
g(-sqrt(5/2))=-9/4
The answer is sqrt(5/2) and -sqrt(5/2).

4 0
3 years ago
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PLS HELP ASAP THIS IS DUE IN 10 MINUTES
olchik [2.2K]

Answer:A number decreased by 40

Step-by-step explanation: I really don't feel like explaining this lol...

8 0
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