Question

In circle K , diameter CD is drawn and point E is located on the circle such that CE=16 and DE=30 .What is the length of the radius of circle K?

Answer 1

Answer:

The length of the radius of the circle K is $17\ units$

Step-by-step explanation:

we know that

The triangle CDE is a right triangle with the 90 degree angle at point E

so

Applying the Pythagoras Theorem

Find the length of CD (diameter of the circle K)

$CD^{2}=CE^{2}+DE^{2}$

substitute the values

$CD^{2}=16^{2}+30^{2}$

$CD^{2}=1,156$

$CD=34\ units$

Find the radius

Remember that the radius is half the diameter

so

$r=34/2=17\ units$