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Alchen [17]
4 years ago
11

A line passes through the points ( – 4, – 2) and ( - 1, - 2). Determine the slope of the line.

Mathematics
1 answer:
Veseljchak [2.6K]4 years ago
4 0

Answer: -4/3

Step-by-step explanation:

Formula to find a slope of two given points is

y(sub2) - y(sub1) / x(sub2) - x(sub1)

Plug the values in to get the answer.

-2 - 2 / -1 - (-4)

-4/3

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What is othorgraphic​
valentinak56 [21]
The conventional spelling system of a language.
3 0
3 years ago
Find the mean 28,18,19,18,17
olga2289 [7]
To find the mean you add up all the numbers then divide the answer by the amount of numbers there are

in this case we add 28+ 18+ 19+ 18+ 17 then divide by 5

THE MEAN IS 20!!!

-HAVE A NICE DAY!!!
7 0
2 years ago
Read 2 more answers
It is known that Ayrshire cattle produce a mean of 49 pounds of milk per day, with a standard deviation of 5 pounds. A dairy far
Phoenix [80]

Answer:

3.67% probability that the mean daily production exceeds 50 pounds.

Step-by-step explanation:

To solve this problem, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 49, \sigma = 5, n = 80, s = \frac{5}{\sqrt{80}} = 0.559

For this herd of 80 cattle, what is the probability that the mean daily production exceeds 50 pounds?

This probability is 1 subtracted by the value of Z when X = 50. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{50 - 49}{0.559}

Z = 1.79

Z = 1.79 has a pvalue of 0.9633

1 - 0.9633 = 0.0367

3.67% probability that the mean daily production exceeds 50 pounds.

8 0
3 years ago
The rectangle shown has a perimeter of 102 cm and the given area. Its length is 6 more than four times
Norma-Jean [14]
The rectangle has two sides of length L and two sides of length W. The perimeter of the rectangle is the addition of all sides.

P = 2L + 2W

We are told the length is 6 more than 4 times its width. Therefore, we can write:

L = 4W + 6

We know the perimeter, and we can now substitute L into the perimeter equation and solve for W.

2L + 2W = P
2(4W + 6) + 2W = 102
6W + 12 + 2W = 102
8W = 90
W = 11.25 cm

We have solved the width as 11.25 cm and can now solve for the length.

L = 4W + 6
L = 4(11.25) + 6
L = 45 + 6
L = 51 cm

The length of the rectangle is 51 cm, the width of the rectangle is 11.25 cm.
6 0
3 years ago
PLEASE HELP BABES!!
KatRina [158]
They did eat:
10/16
But you have to simplify that to:
5/8

Your answer is:
<span>A) 5/8 pie
</span>
Good Luck!
Hope This Helps :)
7 0
3 years ago
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