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Readme [11.4K]
3 years ago
5

Which line is parallel to a line whose slope is 2/5

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
8 0
Line p,with a slope of 2/5 cause when they are parallel the two slopes should be equal
kompoz [17]3 years ago
4 0
<span>The line that is parallel to a line whose slope is 2/5 is:

 </span>
<span>line p, with a slope of 2/5

For two lines to be parallel they must have same slope.
</span>
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Please I need someone to help my assignment​
Nadusha1986 [10]
(x-4)² + (x-2)² = x²

(x² - 8x + 16 ) + (x² - 4x + 4) = x

2x² -12x + 20 = x

2x²-12x + 20 - x = 0

2x² - 13x + 20 = 0

(2x-5) (x-4) = 0

2x-5 = 0

2x = 5

x = ⁵/₂


x-4 = 0

x = 4



so x₁ = ⁵/₂ , and x₂ = 4
4 0
2 years ago
Which graph shows the solution to the system of linear inequalities?
Brilliant_brown [7]

Answer:

this is answer

Step-by-step explanation:

To graph a linear inequality in two variables (say, x and y ), first get y alone on one side. Then consider the related equation obtained by changing the inequality sign to an equality sign. The graph of this equation is a line. If the inequality is strict ( < or > ), graph a dashed line.

4 0
2 years ago
(12x - 2y + 3/5) - (1/4 - 8x + 6y)
Neko [114]

Answer:

20x-8y+ 7/20

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f
castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean (\mu) = 115 \times 20

= 2300

Standard deviation = 20 \times \sqrt{115}

Standard deviation (SD) = 214.4761

TO find:

a) P(x > 3500)= P(Z > \dfrac{3500-\mu}{214.4761})

P(x > 3500)= P(Z > \dfrac{3500-2300}{214.4761})

P(x > 3500)= P(Z > \dfrac{1200}{214.4761})

P(x > 3500)= P(Z >5.595)

From the Z-table, since 5.595 is > 3.999

P(x > 3500)=1-0.9999

P(x > 3500) = 0.0001

b)

Here, the replacement time for the mean (\mu) = \dfrac{0+0.5}{2}

= 0.25

Replacement time for the Standard deviation \sigma = \dfrac{0.5-0}{\sqrt{12}}

\sigma = 0.1443

For 115 component, the mean time = (115 × 20)+(114×0.25)

= 2300 + 28.5

= 2328.5

Standard deviation = \sqrt{(115\times 20^2) +(114\times (0.1443)^2)}

= \sqrt{(115\times 400) +(114\times 0.02082249}

= \sqrt{(46000) +2.37376386}

= \sqrt{(46000) +(2.37376386)}

= \sqrt{46002.374}

= 214.482

Now; the required probability:

P(x > 4125) = P(Z > \dfrac{4125- 2328.5}{214.482})

P(x > 4125) = P(Z > \dfrac{1796.5}{214.482})

P(x > 4125) = P(Z >8.376)

P(x > 4125) =1-  P(Z

From the Z-table, since 8.376 is > 3.999

P(x > 4125) = 1 - 0.9999

P(x > 4125) = 0.0001

7 0
2 years ago
What is bigger 1/5 or .29
n200080 [17]
.29 is bigger.

If you convert 1/5 to a decimal (or simply solve it!) you will end up with .2 or .20
Which is obviously smaller than .29
3 0
3 years ago
Read 2 more answers
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