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puteri [66]
3 years ago
8

What is the standard form that has a center (1,3) and a radius of 9

Mathematics
1 answer:
klasskru [66]3 years ago
4 0

\huge\boxed{(x-1)^2+(y-3)^2=9^2}

Start with the standard form of a circle, where (h,k) is the center of the circle and r is the radius.

(x-h)^2+(y-k)^2=r^2

Plug in the known values.

\boxed{(x-1)^2+(y-3)^2=9^2}

This is the circle's equation in standard form.

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Xby the power of 5 times y to the power of 6 over 2 by the power of -2 times xby the power of 0times x by the power of 9
mars1129 [50]

Answer:

We have the sentence:

"X by the power of 5 times y to the power of 6 over 2 by the power of -2 times x by the power of 0times x by the power of 9"

Let's break it into parts.

"X by the power of 5 times y to the power of 6..."

This can be written as:

x^5*y^6

"...  2 by the power of -2 times x by the power of 0times x by the power of 9"

This can be written as:

2^(-2)*x^(0)*x^(9)

And we have the quotient between the first thing and the second thing, then the equation is:

\frac{x^5*y^6}{2^{-2}*x^0*x^9}

And any number by the power of 0 is equal to 1, then:

x^0 = 1, then we can rewrite the equation as:

\frac{x^5*y^6}{2^{-2}*x^9}

We can keep simplifying this.

We know that:

a^(-n) = (1/a)^(n)

Then:

2^(-2) = (1/2)^2 = 1/4

Then we get:

\frac{x^5*y^6}{2^{-2}*x^9} = \frac{x^5*y^6}{x^9}*4

And we also know that:

a^n/a^m = a^(n - m)

Then:

\frac{x^5*y^6}{x^9}*4 = 4*y^6*\frac{x^5}{x^9} = 4*y^6*x^{5 - 9} = 4*y^6*x^{-4} = \frac{4*y^6}{x^4}

And we can't simplify this anymore.

8 0
3 years ago
Can somebody please help me out please my grads are bad
Schach [20]

Step-by-step explanation:

Starting from the upper left in the clockwise direction:

congruent: no

similar: no

upper right side:

congruent: yes

similar: yes

lower right side:

congruent: no

similar: yes

lower left side:

congruent: yes

similar: yes

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This question is worth 100 points if you get this right.
stiv31 [10]

Answer:

it will take 7 nights

Step-by-step explanation:

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What is the slope-intercept equation<br> for the following line?<br> y = [?]x + []
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