What is the slope of y-4=5/2(x-2)
1 answer:
The answer is 5/2. The equation is already in point slope form. If you recall, the equation for point slope form is y-y1 = m(x-x1) where y1 and x1 are points on the graph, and m is the slope. In the given equation, m is 5/2 so we know it is the slope.
Alternatively, if you are not familiar with the point slope for equation, you can manipulate the equation to the form of y=mx+b where m is the slope and b is the constant. If you solve for y, you get y=5/2x-1 since 5/2 is in the place of m, we know 5/2 is the slope.
Alternatively, if you are not familiar with the point slope for equation, you can manipulate the equation to the form of y=mx+b where m is the slope and b is the constant. If you solve for y, you get y=5/2x-1 since 5/2 is in the place of m, we know 5/2 is the slope.
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Answer:
The correct option is;
B. 50 km/h
Step-by-step explanation:
The information given in the question are;
The distance between the two cities = 140 km
The direction of motion of the first car = From A to B (left)
The direction of motion of the second car = From B to A
The time after which both cars meet = 1 hour
The time duration it takes after both cars meet for the second car to reach A = 35 minutes
The total time taken by the second car from city B to city A = The time it takes to meet the first car + The time it takes after meeting the first car to reach city A
∴ The total time taken by the second car from city B to city A = 1 hour + 35 minutes = 60 minutes + 35 minutes = 95 minutes
95 minutes = 95/60 hours = 1⁷/₁₂ hours = 1.58 hours
The speed of the second car = Distance/Time = 140 km/(1.58 hours) ≈ 88.42 km/h
Therefore, let the distance from A of the point the first car meet the second car = x
Therefore, we have;
The distance from B of the point both cars meet = (140 - x) km
Given that both cars meet after one hour, we have;
The distance travelled by the second car coming from city B, after one hour = (140 - x) km = Speed of the second car × 1 hour
88.42 km/h × 1 hour = 88.42 km = (140 - x) km
x = 140 - 88.42 ≈ 51.58 km
The distance from A of the point the first car meet the second car = x = 51.58 km
The speed of car A = (The distance from A of the point the first car meet the second car)/(Time it takes both cars to meet)
∴ The speed of the first car = 51.58 km/(1 hour)
The speed of the first car = 51.58 km/h ≈ 50 km/h (Rounding up to the nearest 10th).