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2 years ago

The bar graph shown here provides the numbers of scoops of different ice cream flavors that were sold during school lunch today.

Mathematics

2 answers:

Mila [183]2 years ago

3 0

C is the answer because 10 - 6 = 4 and 6 + 4 = 10

sattari [20]2 years ago

3 0

From the graph:

10 scoops of strawberry were sold;

6 scoops of vanilla were sold;

I'll let you do the rest.

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Write 7.5% as a fraction in lowest terms

denis-greek [22]

I believe the answer would be 3/40

3 0

3 years ago

I'm confused can someone help me

Dafna11 [192]

Answer: M∠2 just mean measure of angle 2,

Step-by-step explanation: So I worked it out and the awnser is B.

3 numbers/the degrees of all 3 sides always add up to 180 degrees.

Side 1 is 60 degrees and the left side is 20, so 20 + 60 + 3 (unkown number) = 180

60 - 20 = 100,

8 0

2 years ago

A contractor purchases 4 dozen pairs of padded work gloves for $56.16. He incorrectly calculates the unit price as $14.04 per pa

xenn [34]

Answer:

$1.17 per glove

Step-by-step explanation:

56.16 divided by 4 then divide that number by 12

7 0

2 years ago

The following scatter plot represents the number of views a video gets each day.

N76 [4]

Answer:

y = 1.0535(4.9512)^x

It can be considered a viral video

Step-by-step explanation:

Using the exponential regression calculator, the regression model obtained is :

y = 1.0535(4.9512)^x

Using the model, we can determine if a video can be considered viral ;

Number of days, x = 10

y = 1.0535(4.9512)^10

y = 1.0535(8853290.1338)

y = 9,326,941.15

Hence, video will receive way over 3 million reviews, a review of about 9,326,941, hence, it can be considered a viral video.

6 0

1 year ago

Given f(x) =

sergejj [24]

Answer:

Step-by-step explanation:

We are given the function:

$\displaystyle f(x) = \left\{ \begin{array}{ll} 2\cos(\pi x) \text{ for } x \leq -1 \\ \\ \displaystyle \frac{2}{\cos(\pi x)}\text{ for } x > -1 \end{array} \right.$

And we want to find:

$\displaystyle \lim_{x\to -1}f(x)$

So, we need to determine whether or not the limit exists. In other words, we will find the two one-sided limits.

Left-Hand Limit:

$\displaystyle \lim_{x\to-1^-}f(x)$

Since we are approaching from the left, we will use the first equation:

$\displaystyle =\lim_{x\to -1^-}2\cos(\pi x)$

By direct substitution:

$=2\cos(\pi (-1))=2\cos(-\pi)=2(-1)=-2$

Right-Hand Limit:

$\displaystyle \lim_{x\to -1^+}f(x)$

Since we are approaching from the right, we will use the second equation:

$=\displaystyle \lim_{x\to -1^+}\frac{2}{\cos(\pi x)}$

Direct substitution:

$\displaystyle =\frac{2}{\cos(\pi (-1))}=\frac{2}{\cos(-\pi)}=\frac{2}{(-1)}=-2$

So, we can see that:

$\displaystyle \displaystyle \lim_{x\to-1^-}f(x)=\displaystyle \lim_{x\to -1^+}f(x) =-2$

Since both the left- and right-hand limits exist and equal the same thing, we can conclude that:

$\displaystyle \lim_{x \to -1}f(x)=-2$

Our answer is A.

8 0

2 years ago