Answer:
225.78 grams
Step-by-step explanation:
To solve this question, we would be using the formula
P(t) = Po × 2^t/n
Where P(t) = Remaining amount after r hours
Po = Initial amount
t = Time
In the question,
Where P(t) = Remaining amount after r hours = unknown
Po = Initial amount = 537
t = Time = 10 days
P(t) = 537 × 2^(10/)
P(t) = 225.78 grams
Therefore, the amount of iodine-131 left after 10 days = 225.78 grams
The graph of

is shown in the graph below.
The graph is of ∩-shape when the constant

of the quadratic equation

is negative
Answer:
3/4
Step-by-step explanation:
Since we have two points, we can use the slope formula
m = ( y2-y1)/(x2-x1)
= ( 5 - -1)/( 4 - -4)
= ( 5+1)/(4+4)
= 6/8
= 3/4
Answer:
7 reservoirs
Step-by-step explanation:
1 yards = 3 feet => 3.5 yards = 10.5 feet
To determine how many numbers of reservoirs to reserve 90000, we first need to determine the capacity of each reservoirs (how much liquid one reservoir can contain) - which is equal to the volume.
The formula to calculate the volume of a circular cylinder is:
- <em>Volume of cylinder = Area of base x Height </em>
<em />
The base of this cylinder is a circle with radius equal to 4 feet. (
)
=> The are of the base is =
= 3.14 x 4^2 = 50.24 feet square
=> The volume of cylinder = Area of base x Height
=> The volume of one cylinder = 50.24 x 10.5 = 527.52 Cubic foot
We have: 1 cubic foot = 28.317 liters
=> 1 liter = 1/28.317 cubic foot
=> 90000 liters equal to: 90000/28.317 = 3,178.303 cubic foot
The number of reservoirs needed to contain 90000 liters of liquid is:
3,178.303/527.52 = 6.025
=> So that it needs 7 reservoirs to store all 90000 liters of liquid.