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Deffense [45]
3 years ago
15

60×4=____tens×4=__tens=___

Mathematics
2 answers:
UNO [17]3 years ago
4 0
60x4=6 tens x 4=24 tens= 240
BaLLatris [955]3 years ago
3 0

Answer: 60×4= <u>6</u> tens×4 = <u>24 </u>tens = 240


Step-by-step explanation:

Given product= 60×4

we know that place value of 6 is tens, thus we can write 60=6 tens , such that the product becomes

60×4=6 tens×4

⇒ 4 times 6 tens

=6 tens+6 tens+6 tens+6 tens

=24 tens

We know that 24 tens id equivalent to 240

thus, 24 tens =240

Therefore, 60×4= <u>6</u> tens×4 = <u>24 </u>tens = 240

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What is the greatest common factor of 12 and 90?
qwelly [4]
The greatest common factor (gcf) is 6.
4 0
3 years ago
2.please I need help
Anarel [89]

9514 1404 393

Answer:

  1. 48°
  2. 60°
  3. 72°

Step-by-step explanation:

The sum of ratio units is 4+5+6 = 15, so each unit stands for 180°/15 = 12°. Multiplying the ratio units by 12° gives the angle values:

  4×12° : 5×12° : 6×12° = 48° : 60° : 72°

Angles 1 to 3 are 48°, 60°, 72°, respectively.

7 0
3 years ago
Find the domain and range of the following graph.
shutvik [7]

Remember that the <em>domain</em> is the set of all the x terms.

So in the graph shown here, notice that the x terms seem to be increasing in both a positive and negative direction and there seems to be no limit to how large or how small the x terms can get. So the x terms can be all positive and negative numbers, including decimals and fractions.

In other words, the x terms can be All Real Numbers.

So the domain is equal to the set of all real numbers or <em>R</em>.

The range is the set of all the y terms.

Notice that all the y terms are less than or equal to 9.

So the range is {y: y ≤ 9}.

8 0
3 years ago
Elan is painting the outside of a rectangular barn door. It is
UkoKoshka [18]

Answer:

9600

Step-by-step explanation:

80 times 60 times 2

5 0
3 years ago
Part B
Troyanec [42]

Answer:

Part A) The length of a straight line between the school and the Fire Station is 4.6\ miles

Part B) The length of a straight line between the school and the hospital is 2.1\ miles

Step-by-step explanation:

<u><em>The complete question in the attached figure</em></u>

Let

The positive x-coordinates ----> East

The positive y-coordinates ----> North

The negative x-coordinates ----> West

The negative y-coordinates ----> South

take the point A (0,0) as the Middle School (reference point)

Part A) we have

Town Hall is located 4.3 miles directly east of the Middle School

so

The coordinates of Town Hall are B(4.3,0)

The Fire Station is located 1.7 miles directly North of Town Hall

so

The coordinates of Fire Station are C(4.3,1.7)

What is the length of a straight line between the school and the Fire Station?

Remember that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

A(0,0) and C(4.3,1.7)

substitute

d=\sqrt{(1.7-0)^{2}+(4.3-0)^{2}}

d=\sqrt{(1.7)^{2}+(4.3)^{2}}

d=4.6\ miles

Part B) we have that

The hospital is 3.1 miles west of the fire station

so

The coordinates of the hospital are D(4.3-3.1,1.7)

D(1.2,1.7)

What is the length of a straight line between the school and the hospital?

Remember that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

A(0,0) and D(1.2,1.7)

substitute

d=\sqrt{(1.7-0)^{2}+(1.2-0)^{2}}

d=\sqrt{(1.7)^{2}+(1.2)^{2}}

d=2.1\ miles

7 0
3 years ago
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