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4 years ago

What is the domain and range of (-6,3), (-1,2), (0,3), (2,4), (5, -1)

Mathematics

2 answers:

Nat2105 [25]4 years ago

8 0

D͓̽o͓̽m͓̽a͓̽i͓̽n͓̽: {-6 ≥x͓̽≤ 5}

R͓̽a͓̽n͓̽g͓̽e͓̽: {-1 ≥y͓̽≤ 4}

qaws [65]4 years ago

4 0

Domain: -6, -1, 0, 2, 5
Range: 3, 2, 4, -1

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In a class of 40 students, everyone has either a pierced nose or a pierced ear. The professor asks everyone with a pierced nose

stepan [7]

2 students have both their nose and ears pierced

6 0

3 years ago

Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th

trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

t = 20: 999 fishes

t = 30: 1168 fishes

(c)

$P(\infty) = 1200$

Step-by-step explanation:

Given

$P(t) =\frac{d}{1+ke^-{ct}}$

$d = 1200\\k = 11\\c=0.2$

Solving (a): Fishes at t = 0

This gives:

$P(0) =\frac{1200}{1+11*e^-{0.2*0}}$

$P(0) =\frac{1200}{1+11*e^-{0}}$

$P(0) =\frac{1200}{1+11*1}$

$P(0) =\frac{1200}{1+11}$

$P(0) =\frac{1200}{12}$

$P(0) = 100$

Solving (a): Fishes at t = 10, 20, 30

$t = 10$

$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

$t = 30$

$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

5 0

3 years ago

atroni [7]

Answer:

I believe the question says "5j + 16 - 12(-9j - 4) - 12j" I hope I'm correct because I have almost no idea what you typed.

If you did type "5j + 16 - 12(-9j - 4) - 12j" then your answer would be 133j + 52 I believe. You never put how you would like your problem to be solved, so I simplified.

Step-by-step explanation:

Hope this helps.

5 0

3 years ago

Solve for x and y.

Rus_ich [418]

y is $8\sqrt{3}$ . This is because in a 30-60-90 triangle, the side facing the 30° is always half of the side facing the 90°

x is always √3 times y, so x=24. Therefore, the answer is the second answer choice.

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3 years ago

Read 2 more answers

The wait time to ride the thunder boats is 30 minutes when 180 people are in line. Write and solve a proportion to find the wait

mars1129 [50]

SO EASY 60 people = 10 minutes in line 240 people = 40 minutes in line

6 0

3 years ago