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4 years ago

Which of the following is the most stable carbocation ?

Chemistry

1 answer:

lutik1710 [3]4 years ago

5 0

Answer:

Explanation:

C have maximum number of aplha H

(alpha H: it's is the total number of hydrogen attached to the adjacent carbon atoms; maxmimum the number maximum the stability of compound)✌️;)

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Evgen [1.6K]

Answer:

Hmm, what can I help you with?

Explanation:

5 0

3 years ago

Which two electron configurations represent elements that would have similar chemical properties? (1) 1s22s22p4 (2) 1s22s22p5 (3

Anton [14]

Answer: Two electron configurations of elements that would have similar chemical properties are (2) and (4).

Explanation:

(1) $1s^22s^22p^4$

(2) $1s^22s^22p^5$

(3) $[Ar]4s^23d^5$

(4) $[Ar]4s^23d^{10}^4p^5$

Valence electrons : These are the electrons present in last principal quantum number of an atom of the element.

Two electron configurations represent elements that would have similar chemical properties are (2) and (4). This is because number of valence electrons present in both of them are same that is seven valence electrons . Also valence electrons of both the elements are present in p-orbital which means that they both belongs to same group in a periodic table. The members of same group in a periodic table have similar chemical properties.

3 0

3 years ago

What makes and acid an acid?

Crank

Answer: The donating of hydrogen ions is what makes an acid an acid. A base, however, is a substance that accepts hydrogen ions.

Explanation:

8 0

4 years ago

Determine the molar mass of CuSO4 (the solute) in a 1.0M aqueous solution of CuSO4

inna [77]

Answer:

See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

$M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol$

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

$M=\frac{n_{solute}}{V_{solution}}$

So you can solve for the moles of the solute:

$n_{solute}=M*V_{solution}$

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

$n_{solute}=1mol/L*1.5L=1.5mol$

But this is just a supposition.

Regards.

4 0

3 years ago

(e) A 0.050 mol sample of a hydrocarbon was burned in excess oxygen.

LenKa [72]

The correct answer is 0.15.

We are aware that there is 0.05 mol of an unidentified hydrocarbon we will refer to as "X" and that its burning produces 6.6 g of carbon dioxide and 3.6 g of water.

These quantities might be converted to moles by applying the following formula:

amount= mass/ relative atomic mass

Thus, the following equation may be written for H2O: moles = 3.6 / 18 = 0.2 and for CO2: moles = 6.6 / 44 = 0.15.

0.05X + x'O2 = 0.15CO2 + 0.2H2O

This may be made simpler by dividing through by 0.05 (this step is likely to be the most helpful to you), resulting in:

1 x + x O2 = 3 co2 + 4 H2O

The hydrocarbon must have been the source of all the carbon in the carbon dioxide and all the hydrogen in the water.

Accordingly, 4 x 2 = 8 moles of H and 3 x 1 = 3 moles of C.

There are 3/1 = 3 Cs and 8/1 = 8 Hs in one X molecule.

This clearly identifies C3H8 or propane as the hydrocarbon X (dividing by 1 seems unnecessary, but it illustrates the process to use if there were more than one mol of X in the first equation).

To learn more about number of moles of carbon dioxide refer the link:

brainly.com/question/12723070

#SPJ9

6 0

2 years ago