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cricket20 [7]
3 years ago
8

What is the ratio of Fe ions to O ions in a neutral compound?

Chemistry
2 answers:
Dovator [93]3 years ago
8 0

The answer is 2:3 100%


AVprozaik [17]3 years ago
3 0
1:1

Fe has a charge of 2+ while O has a charge of 2-.

Formula: FeO
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Why is blood typing considered codominance and multiple alleles
Alecsey [184]

Answer:

An example of multiple alleles is the ABO blood-type system in humans. In this case, the IA and IB alleles are codominant with each other and are both dominant over the i allele. Although there are three alleles present in a population, each individual only gets two of the alleles from their parents.

6 0
2 years ago
Indicate whether each of the following statements is correct or incorrect.1)Every Bronsted-Lowry acid is also a Lewis acid2)Ever
Hunter-Best [27]

Answer:

1) correct

2) incorrect

3) correct

4)incorrect

Explanation:

1) A Lewis acid is a substance that accepts a nonbonding pair of electrons.

A Bronsted-Lowry acid is a substance that donates a proton H⁺

Since the donation of a proton involves the acceptance of a pair of electrons, every Bronsted-Lowry acid is also a Lewis acid.

2)A Lewis acid not necessarily needs to have a proton to be donated.

3) Conjugated acids of weak bases are strong acids and conjugated acids of strong bases are weak acids.

4)K⁺ comes from a strong base, therefore is does not have an acidic behaviour.

4 0
3 years ago
If you increase the solute amount but keep the solution volume the same what
solmaris [256]

Answer: Molarity increases

Explanation:

Molarity, also known as concentration in moles/dm3 or g/dm3, is calculated by dividing the amount of solute dissolved by the volume of solvent. So, Molarity (c) = amount of solute (n) / volume (v)

i.e c = n/v

Hence, molarity is directly proportional to the amount of solute dissolved, and inversely proportional to the volume of solvent.

Thus, at same volume, any increase in solute amount increases molarity while a decrease will also decreases molarity.

4 0
3 years ago
What is the sequence of coefficients that will balance the following decomposition reaction of dihydrogen monosulfide? H₂S ----&
RUDIKE [14]

8 S

In this case you must start balancing the sulfur to have 8 on each side of the reaction. So:

Answer:

Explanation:

The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

Then, you must balance the chemical equation. For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts.  

The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.

By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.

Then, taking into account all of the above, you can determine the amount of elements on each side of the equation:

Left side: 2 H and 1 S

Right side: 2 H and 8 S

In this case you must start balancing the sulfur to have 8 on each side of the reaction. So:

8 H₂S → H₂ + S₈

Now the amount of elements on each side of the equation:

Left side: 16 H and 8  

Right side: 2 H and 8 S

Now you need to start balancing the hydrogen to get the same amount from each side of the reaction. So:

8 H₂S → 8 H₂ + S₈

Now the amount of elements on each side of the equation:

Left side: 16 H and 8  

Right side: 16 H and 8 S

<u><em>The balanced reaction is:</em></u>

<u><em>8 H₂S → 8 H₂ + S₈</em></u>

3 0
2 years ago
The reaction A(B) = 2B(g) has an equilibrium constant of K = 0.045. What is the equilibrium constant for the reaction B(g) =1/2A
Mamont248 [21]

Answer:

The  K_c for the reaction B(g) = \frac{1}{2}A will be 4.69.

Explanation:

The given equation is A(B) = 2B(g)

to evaluate equilibrium constant for B(g) = \frac{1}{2}A

            K_c=[B]^2[A]

                 = 0.045

The reverse will be 2B\leftrightharpoons A

Then,      K_c = \frac{[A]}{[B]^2}

                    =  \frac{1}{0.045}

                    = 22m^{-1}

The equilibrium constant for B(g) = \frac{1}{2}A will be

               K_c = \sqrt{K_c}

                    =\sqrt{22}

                    = 4.69

Therefore, K_c for the reaction B(g) = \frac{1}{2}A will be 4.69.

5 0
3 years ago
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