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4 years ago

What is the product of 4x4y2 and 5y4?

Mathematics

1 answer:

Inessa05 [86]4 years ago

8 0

Answer:

20 $x^{4}$ $y^{6}$

Step-by-step explanation:

using the law of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$

4 $x^{4}$ $y^{2}$ × 5 $y^{4}$

= (4 × 5 ) × $x^{4}$ × $y^{(2+4)}$

= 20 $x^{4}$ $y^{6}$

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3 years ago

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4 years ago

If cot theta= 4/3, find csc theta

Marrrta [24]

Answer: Option d.

Step-by-step explanation:

The trigonometric identity needed is:

$csc^2\theta=cot^2\theta+1$

Knowing that $cot\theta=\frac{4}{3}$ :

Substitute it into $csc^2\theta=cot^2\theta+1$ :

$csc^2\theta=(\frac{4}{3})^2+1$

Simplify the expression:

$csc^2\theta=(\frac{4}{3})^2+1\\\\csc^2\theta=\frac{16}{9}+1\\\\csc^2\theta=\frac{25}{9}$

Solve for $csc\theta$ . Apply square root at both sides of the expression:

$\sqrt{csc^2\theta}=\±\sqrt{\frac{25}{9}}$

$csc\theta=\frac{5}{3}$

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