We have trapezoid with congruent legs.
30x + 11y = 2x + 3
28x +11y = 3
Also we have
30x + 11y = 12
We got 2 equations:
30x + 11y = 12
28x +11y = 3 (*-1) -----> -28x -11y = -3
30x + 11y = 12
<u> -28x -11y = -3</u>
2x = 9
x=9/2
30x + 11y = 12 ------> 30*9/2 +11y =12 ------> 135+11y =12, ---> 11y = - 123,
y= - 123/11
For f(x), 6 represents x here, so we plug 6 in for x to get 2*6²+5√(6-2). Using PEMDAS, we get 72+5√4=72+5*2=72+10=82
Huh?
You forgot something.
3(6x+2)-18x=12 (y=6x+2, so you plug in 6x+2 into the y in 3y-18x=12)
18x+6-18x=12 (Then you distribute the 3 to the 6x and to the 2)
6=12 (Combine like terms 18x-18x)
There is no solution. Hope this helps and makes sense.
So I would first find out when they are equal then do one more than that. 21x=18x+45, 3x=45, x=15 so the answer would be 16 jerseys
