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3 years ago

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The edges of a cube are 5 centimeters each and the diagonal of a face is approximately 7 centimeters. What is the approximate ar

ea of the cross section passing through the diagonals of opposite faces of this cube? A. 12 square centimeters B. 25 square centimeters C. 35 square centimeters D. 49 square centimeters

1 answer:

Naddika [18.5K]3 years ago

4 0

Answer:

C

Step-by-step explanation:

5x7=35. Unfortunately I can't show you a model to explain further.

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The sum of two consecutive even number's is 66. find the numbers.

Elena L [17]

Answer:

$32\ and\ 34.$

Step-by-step explanation:

Let x be the smaller number.

The next even number will be (x + 2).

$x+x+2=66$

$2x+2=66$

Subtract 2 from both sides:

$2x+2-2=66-2$

$2x=64$

Divide both sides by 2:

$\frac{2x}{2}=\frac{64}{2}$

$x=32$

The smaller number is 32.

Larger number $=32+2=34$

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3 years ago

!!I’LL MARK YOU BRAINLIEST PLS HELP!!

Sloan [31]

Answer:

Because it is more wholes

Step-by-step explanation:

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3 years ago

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MUST SHOW WORK. <br> please do this ASAP!<br> This is about numerical expressions!

lara31 [8.8K]

$\huge\text{Hey there!}$

$\mathsf{2(4 - 1)^2 - 3 + 2(5)}$

$\mathsf{4 - 1 = \bf 3}$

$\mathsf{= 2(3^2) - 3 + 2(5)}$

$\mathsf{3^2}\\\mathsf{= 3\times3}\\\mathsf{= \bf 9}$

$\mathsf{= 2(9) - 3 + 2(5)}$

$\mathsf{2(9)}\\\mathsf{= \bf 18}$

$\mathsf{= 18 - 3 + 2(5)}$

$\mathsf{18 - 3}\\\mathsf{= \bf 15}$

$\mathsf{= 15 + 2(5)}$

$\mathsf{2(5)}\\\mathsf{= \bf 10}$

$\mathsf{= 15 + 10}\\\mathsf{= \bf 25}$

$\boxed{\boxed{\huge\text{Therefore, your ANSWER is: \textsf{25}}}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day! }$

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3 years ago

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Which functions are symmetric with respect to the origin?

Damm [24]

Answer:

The correct option is;

y = arcsinx and y = arctanx

Step-by-step explanation:

The given options are;

1) y = arcsinx and y = arccosx

Here, we have at the origin, where x = 0, arccosx ≈ 1.57 while arcsinx = 0

Therefore arccosx does not intersect arcsinx at the origin for it to be symmetrical to arcsinx or the origin

2) y = arccosxy and y = arctanx

Here arctanx = 0 when x = 0 and arcos x = 1.57 when x = 0 therefore, they are not symmetrical

3) y = arctanx and y = arccotx

Similarly, At x = 0, arccotx = 1.57 therefore, they are not symmetrical

4) y = arcsinx and y = arctanx

Both functions arcsinx and arctanx pass through the origin and their shapes are similar but inverted as they go from negative to positive.

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3 years ago

Ax + c = R (solve for x)

sp2606 [1]

Ax + c = R (subtract c from each side)

Ax + c - c = R - c

Ax = R - c (divide A from each side)

Ax/A = (R-c)/A

x = $\frac{R-c}{A}$ <-answer

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2 years ago

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