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stich3 [128]
2 years ago
7

If 10 miles=16km, about how many miles would be equal to 76 km?​

Mathematics
2 answers:
Allisa [31]2 years ago
8 0
If you add 16 5 times you get 80 and if you only add 16 4 times you get 64 so figure that probably like, 50 miles
Shalnov [3]2 years ago
6 0

it would be 7 lolz dheisns

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The diagram below shows the dimensions of a triangular park built in a new housing development. Two side lengths and one angle m
evablogger [386]
ANSWER

x = 50.5 \degree

EXPLANATION

We use the sine rule for solving triangles.

This is given by the formula,


\frac{ \sin(A) }{a}  =  \frac{ \sin(B) }{b}  = \frac{ \sin(C) }{c}


From the triangle,

\frac{ \sin(x) }{60}  =  \frac{ \sin(40) }{50}

We multiply both sides of the equation by 60 to get,

sin(x)  =  \frac{ 60\sin(40 \degree) }{50}


sin(x)  = 0.7713



We solve for x to obtain,

x = arcsin(0.7713)


x = 50.475

To the nearest tenth, we round to one decimal place to get,

x = 50.5 \degree

7 0
3 years ago
The area of another rectangle is x² + 5x + 6. If one side measures (x + 2), what is the measure of the other
tiny-mole [99]
  • L=x+2
  • We need B

\\ \sf\longmapsto LB=Area

\\ \sf\longmapsto B(x+2)=x^2+5x+6

\\ \sf\longmapsto B(x+2)=(x+2)(x+3)

  • Cancel x+2

\\ \sf\longmapsto B=x+3

8 0
2 years ago
Which is the value of this expression when p=-2 and q=-1?
saul85 [17]

Answer:

D. 4

Step-by-step explanation:

[(p^2) (q^{-3}) ]^{-2}.[(p)^{-3}(q)^5] ^{-2}\\\\=[(p^2) (q^{-3}) \times(p)^{-3}(q)^5 ]^{-2}\\\\=[(p^{2}) \times(p)^{-3} \times (q^{-3}) \times(q)^5 ]^{-2}\\\\=[(p^{2-3}) \times (q^{5-3}) ]^{-2}\\\\=[(p^{-1}) \times (q^{2}) ]^{-2}\\\\=(p^{-1\times (-2)}) \times (q^{2\times (-2) }) \\\\=p^{2}\times q^{-4} \\\\= \frac{p^2}{q^4}\\\\= \frac{(-2)^2}{(-1)^4}\\\\= \frac{4}{1}\\\\= 4

8 0
3 years ago
What are narcissistic numbers
konstantin123 [22]
69,420,911,80085 and that’s all
6 0
2 years ago
Use function g, shown in the graph below.
Katyanochek1 [597]
You should search it up on Photomath is easier
5 0
3 years ago
Read 2 more answers
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