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3 years ago

I need help asap I dont het it Get

Mathematics

1 answer:

Mars2501 [29]3 years ago

5 0

Answer:

Step-by-step explanation:

The absolute value of 0 is 0 so 0 = 0 is true.

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Find the standard form of the equation of the circle with endpoints of a diameter at the points (3,8) and (-7,2)

poizon [28]

$(x+2)^{2}$ + $(y-5)^{2}$ = 34

The equation of a circle in standard form is

$(x-a)^{2}$ + $(y-b)^{2}$ = $r^{2}$

where (a , b) are the coordinates of the centre and r is the radius

The centre is at the midpoint of the endpoints and the radius is the distance from the centre to either of the 2 endpoints

Using the midpoint formula

midpoint = [ $\frac{1}{2}$ (x $x_{1}$ + $x_{2}$ , $\frac{1}{2}$ ( $y_{1}$ + $y_{2}$

where ( $x_{1}$ , $y_{1}$ =(3,8) and ( $x_{2}$ , $y_{2}$ =(-7,2)

centre = ( $\frac{1}{2}$ (3-7), $\frac{1}{2}$ (8+2)) = (-2,5)

Calculate r using the distance formula

r = √( $x_{2}$ - $x_{1}$ )²+( $y_{2}$ - $y_{1}$ )²)

= √((3+2)²+(8-5)²) = √(25+9) = √34 ⇒ r² =(√34)² = 34

equation of circle is : (x+2)²+(y-5)² = 34

8 0

3 years ago

(3-4i)(6i+7)-(2-3i)

Sergeu [11.5K]

Answer:

43-7i

Step-by-step explanation:

We are given the expression:

$\displaystyle \large{(3 - 4i)(6i + 7) - (2 - 3i)}$

First, expand 3-4i in 6i+7. To expand binomial with binomial, first we expand 3 in 6i+7 then expand -4i in 6i+7.

$\displaystyle \large{[(3 \cdot 6i) + (3 \cdot 7) + ( - 4i \cdot 6i) + ( - 4i \cdot 7)]- (2 - 3i)} \\ \displaystyle \large{[18i + 21 - 24 {i}^{2} - 28i]- (2 - 3i)}$

Now combine like terms.

$\displaystyle \large{[ - 10i+ 21 - 24 {i}^{2} ]- (2 - 3i)}$

Imaginary Unit

$\displaystyle \large{i = \sqrt{ - 1} } \\ \displaystyle \large{ {i}^{2} = - 1 }$

Therefore:-

$\displaystyle \large{[ - 10i+ 21 - 24 ( - 1) ]- (2 - 3i)} \\ \displaystyle \large{[ - 10i+ 21 + 24]- (2 - 3i)} \\ \displaystyle \large{[ - 10i+ 45]- (2 - 3i)}$

Then expand negative sign in 2-3i; remember that negative times negative is positive and negative times positive is negative.

$\displaystyle \large{- 10i+ 45 - (2 - 3i)} \\ \displaystyle \large{- 10i+ 45 - 2 + 3i}$

Combine like terms.

$\displaystyle \large{43 - 7i}$

5 0

2 years ago

The ratio of the perimeters of two similar triangles is 4:3. What are the areas of these triangles if the sum of their areas is

emmasim [6.3K]

Answer:

the areas of these triangles are 83.2cm² and 46.8cm²

Step-by-step explanation:

1. If the triangles are similar and the ratio of the perimeter ois 4:3, then the areas are in the following ratio:

4²:3²

16:9

2. The sum of their areas is 65 cm², then, you can calculate the area of the larger triangle as following:

130(16/16+9)

130(0.64)

=83.2cm²

3. The area of the smaller triangle is:

130(9/16+9)

130(0.36)

46.8cm²

Hope this helps

6 0

3 years ago

How to add the integers -7 and -5.

Rzqust [24]

-7 + -5
When you add negative, it would be the same as subtracting
Turns into: -7-5
-(7+5) = -12
The solutions is -12

8 0

3 years ago

The ratio of blue jays to Robin's was 6 to 7. If there were 84 Robins, how many blue jays were there?

Paul [167]

Answer:

Step-by-step explanation:

Since the ratio of blue jays to robin's was 6 to 7 then if there were 84 robins how many blue jays were there.

6 to 7 can also be express as 6/7

Thus, we can set up a proportion

6/7 = x/84

Now, we have to solve for x

x = 72

Hence, if there were 84 robin there would be 72 blue jays.

~lenvy~

3 0

2 years ago