The equation of the line would be
y = mx+b
where m is the slope, b is the y intercept.
<span>The line will form a triangular region in the first quadrant. Its area would be 1/2 base times height. The height is the y intercept
and the base is y intercept divided by slope. Therefore,</span>
A = b^2/2m
At point (2,5)
5 = 2m+b
Substitute that in the area
A = b^2/5-b
to find the least area, differentiate the area with respect to the height and equate it to 0
dA/db = 0
<span>find b and
use that to find m. Then, you can have the equation of the line.</span>
This is what you’re looking for !
Answer:
see below
Step-by-step explanation:
12x+24x+18 = 36x+24-6
Combine like terms
36x+18 = 36x+18
Subtract 36x from each side
36x+18-36x = 36x+18-36x
18 = 18
This is always true, so the equation is true for all values of x
12 is divisible by 3 and 4
