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elixir [45]
3 years ago
6

Pq is parallel to rs the length of rp is 6cm the length of pt is 18cm the length of qt is 21cm what is the length of sq

Mathematics
2 answers:
nata0808 [166]3 years ago
8 0
If this is the picture the answer is 7cm 

nlexa [21]3 years ago
3 0

Answer: The length of SQ is 7 cm.

Step-by-step explanation:

Since we have given that

Length of RP = 6cm

Length of PT = 18 cm

Length of QT = 21 cm

We need to find the length of SQ.

Since PQ is parallel to RS.

So, their ratio would be same anyhow.

So, it becomes,

\dfrac{RP}{PT}=\dfrac{SQ}{QT}\\\\\dfrac{6}{18}=\dfrac{SQ}{21}\\\\\dfrac{1}{3}=\dfrac{SQ}{21}\\\\SQ=\dfrac{21}{3}\\\\SQ=7\ cm

Hence, the length of SQ is 7 cm.

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Given log Subscript 3 Baseline 2 almost-equals 0. 631 and log Subscript 3 Baseline 7 almost-equals 1. 771, what is log Subscript
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You can use the properties of logarithm to get to the solution.

The approximate value for given term is given by

log_3(14) \approx 2.402

<h3>What is logarithm and some of its useful properties?</h3>

When you raise a number with an exponent, there comes a result.

Lets say you get

a^b = c

Then, you can write 'b' in terms of 'a' and 'c' using logarithm as follows

b = log_a(c)

Some properties of logarithm are:

log_a(b) = log_a(c) \implies b = c\\\\\log_a(b) + log_a(c) = log_a(b \times c)\\\\log_a(b) - log_a(c) = log_a(\frac{b}{c})

<h3>Using the above properties</h3>

log_3(2) + log_3(7) = log_3(2 \times 7) = log_3(14)\\\\0.631 + 1.771  = log_3(14)\\\\log_3(14) = 2.402

Thus,

The approximate value for given term is given by

log_3(14) \approx 2.402

Learn more about logarithm here:

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For the following geometric sequence find the recursive formula: {-1, 3, -9, ...}.
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3 0
3 years ago
How do I solve for x
Alchen [17]
Greetings!

To find the length of any side of a right triangle, you can use the Pythagorean Thereom. It states that the squares of two sides are equal to the square of the hypotenuse:
a^2+b^2=c^2

Input the information from the diagram into the formula: 
(x)^2+(x+7)^2=(13)^2

Expand each term:
(x)^2+(x+7)^2=(13)^2

x^2+((x+7)(x+7))=169

x^2+(x(x+7)+7(x+7))=169

x^2+x^2+7x+7x+49=169

Combine like terms:
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Add -169 to both sides:
(2x^2+14x+49)+(-169)=(169)+(-169)

2x^2+14x-120=0

Factor out the Common Term (2):
2(x^2+7x-60)=0

Factor the Complex Trinomial:
2(x^2-5x+12x-60)=0

2(x(x-5)+12(x-5))=0

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Set Factors to equal 0:
x-5=0

x=5

or

x+12=0

x=-12

However, since we are solving for the side length, the only possible answer is 5 (a shape can't have a side with a negative length.)

The Solution Is: 
\boxed{x=5}

I hope this helped!
-Benjamin

6 0
3 years ago
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