All categories

3 years ago

Pq is parallel to rs the length of rp is 6cm the length of pt is 18cm the length of qt is 21cm what is the length of sq

Mathematics

2 answers:

nata0808 [166]3 years ago

8 0

If this is the picture the answer is 7cm

nlexa [21]3 years ago

3 0

Answer: The length of SQ is 7 cm.

Step-by-step explanation:

Since we have given that

Length of RP = 6cm

Length of PT = 18 cm

Length of QT = 21 cm

We need to find the length of SQ.

Since PQ is parallel to RS.

So, their ratio would be same anyhow.

So, it becomes,

$\dfrac{RP}{PT}=\dfrac{SQ}{QT}\\\\\dfrac{6}{18}=\dfrac{SQ}{21}\\\\\dfrac{1}{3}=\dfrac{SQ}{21}\\\\SQ=\dfrac{21}{3}\\\\SQ=7\ cm$

Hence, the length of SQ is 7 cm.

You might be interested in

Express the system as AX = B; then solve using matrix inverses

Wittaler [7]

Answer with explanation:

1. The given equations are

3x -5 y=2

-x+2 y= 0

⇒The matrix in the form of , AX=B, is

$A=\left[\begin{array}{cc}3&-5\\-1&2\end{array}\right] ,\\\\ X=\left[\begin{array}{c}x&y\end{array}\right],\\\\B=\left[\begin{array}{c}2&0\end{array}\right]$

$\rightarrow X=A^{-1}B\\\\\rightarrow X=\frac{Adj.A}{|A|}\times B$

Adj.A=Transpose of cofactor of Matrix A

$Adj.A=\left[\begin{array}{cc}2&1\\5&3\end{array}\right] ,\\\\ |A|=6-5\\\\|A|=1\\\\\left[\begin{array}{c}x&y\end{array}\right]=\left[\begin{array}{cc}2&5\\1&3\end{array}\right] \times \left[\begin{array}{c}2&0\end{array}\right]\\\\x=4, y=2$

The given equations are

x+y-z=2

x+z=7

2 x +y+z=13

⇒The matrix in the form of , AX=B, is

$A=\left[\begin{array}{ccc}1&1&-1\\1&0&1\\2&1&1\end{array}\right]\\\\ X=\left[\begin{array}{ccc}x\\y\\z\end{array}\right]\\\\B= \left[\begin{array}{ccc}2\\7\\13\end{array}\right]\\\\\rightarrow X=A^{-1}B\\\\\rightarrow X=\frac{Adj.A}{|A|}\times B\\\\a_{11}=-1,a_{12}=1,a_{13}=1,a_{21}=-2,a_{22}=3,a_{23}=1,a_{31}=1,a_{32}=-2,a_{33}=-1\\\\|A|=1\times(0-1)-1\times(1-2)-1\times(1-0)\\\\=-1+1-1\\\\|A|=-1\\\\Adj.A=\left[\begin{array}{ccc}-1&-2&1\\1&3&-2\\1&1&-1\end{array}\right]$

$\frac{Adj.A}{|A|}=\left[\begin{array}{ccc}1&2&-1\\-1&-3&2\\-1&-1&1\end{array}\right]\\\\X=A^{-1}B\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}1&2&-1\\-1&-3&2\\-1&-1&1\end{array}\right]\times\left[\begin{array}{ccc}2\\7\\13\end{array}\right]\\\\x=3,y=3,z=4$

7 0

3 years ago

6x+3y= -9<br> find the slope and y-intercept

Sophie [7]

Answer:

Slope: -2

y-intercept: -3 or (0, -3)

Step-by-step explanation:

y = mx + b

m = slope

b = y-intercept

6x+3y= -9

3y = -6x - 9

y = -2x - 3

5 0

3 years ago

Read 2 more answers

A 6 inch-tall plant grew 3/4 of an inch week and twice as much the following week. How tall is the plant now?

Alla [95]

8.25 inches once you multiply the 3/4 by 2 and add that and also add the 3/4 from the previous week you’ll get your answer

7 0

3 years ago

Read 2 more answers

Pre-calc<br> Evaluate f(2) using substitution:<br> f(x) = 2x^3 – 3x^2– 18x-8

krek1111 [17]

Answer:

f(2) = -40

Step-by-step explanation:

Just substitute x=2 into the function:

f(x) = 2x³ - 3x² - 18x - 8

f(2) = 2(2)³ - 3(2)² - 18(2) - 8

f(2) = 2(8) - 3(4) - 36 - 8

f(2) = 16 - 12 - 44

f(2) = 4 - 44

f(2) = -40

8 0

2 years ago

What is the image point of (-1,-5) after a translation left 1 unit and up 4 units

TEA [102]

There’s no picture but look for the one that is 0,-1

4 0

3 years ago