Shshhshsxsbsbdbbxbxbfbfbfbdbbdjdjdjdkdd
Answer:
![\left[\begin{array}{ccc}-32\\4\\20\\-36\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-32%5C%5C4%5C%5C20%5C%5C-36%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The product of a scalar times the matrix involves the product of that scalar times each of the elements of the matrix, resulting on the multiplication by "-4" of each of the four elements as shown below. These new product values end up being the new matrix elements.
![-4*\left[\begin{array}{ccc}8\\-1\\-5\\9\end{array}\right] = \left[\begin{array}{ccc}-32\\4\\20\\-36\end{array}\right]](https://tex.z-dn.net/?f=-4%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D8%5C%5C-1%5C%5C-5%5C%5C9%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-32%5C%5C4%5C%5C20%5C%5C-36%5Cend%7Barray%7D%5Cright%5D)
Answer:
Step-by-step explanation:
Let the number be xx
Therefore the product of two and the number is 2xx
If there is eight more than that number, we can say that
2xx + 8
If it is assumed that the equation is equal to zero
2xx + 8 = 0
2xx = -8
xx = -8/2
xx = -4
Answer:
A) mJK = 21
B) mJNM = 159º
C) mKL = 159
D) mJKM = 201
E) mMKL = 339
Step-by-step explanation:
Circle = 360º
360º - 21º = 339º (what all missing angles have to add up to)
Assuming that:
JNL and KNM are both 180º angles
KJ and JM are supplementary as well as KL and LM
If we subtract 21º from 180º we get 159º which is both LM and KL
If we add 21º to 180º we get 201º which is both JKM and LMK
By subtracting 21º from 360º we know that MKL is 339ª
if we add 159º + 159º + 21º we get 339º which proves that those are our missing angles becuase our missing angles must make a total of 339º
Sorry that took so long I was pulling out all my notes from last year to make sure I was doing this right ^^;
The answer is n+7 and 7+n
