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2 years ago

A rectangle board is 1.2 meters long and 0.8 meters wide. What is the area of the board in millimeters

Mathematics

1 answer:

ivanzaharov [21]2 years ago

5 0

Answer:

1200*800 = 960,000 mm²

Step-by-step explanation:

1 meter is 1000 mm and 0.8 meter is 800 mm

A=lw

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2+2-2-3-87+20090 then split in half

Svetllana [295]

20002 because all of it added together and then divided by two gives you 20002.

6 0

3 years ago

Please answer me question 3 solving part

Illusion [34]

Answer:

1. D

2. B

3. A

Step-by-step explanation:

Question 1:

The pair of <JKL and <LKM can be referred to as linear pairs. They are two adjacent angles that are formed from the intersecting of two lines.

Question 2:

Given that <KLM = x°

<KML = 50°

<JKL = (2x - 15)°

According to the exterior angle theorem, exterior ∠ JKL = <KLM + KML.

2x - 15 = x + 50

Solve for x

2x - x = 15 + 50

x = 65

Therefore, <KLM = 65°

QUESTION 3:

<JKL = 2x - 15

Plug in the value of x

<JKL = 2(65) - 15

= 130 - 15

<JKL = 115°

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2 years ago

En una tienda se anuncia la rebaja de 20% en todos sus artículos . Rafael elije una camisa y al llegar a la caja le informan que

dimulka [17.4K]

Responder:

$ 750

Explicación paso a paso:

Dado que :

Descuento en todos los artículos = 20%

Descuento adicional dado = 15%

Monto final pagado por la camisa = $ 510

Precio de la camiseta sin descuento:

Sea el precio inicial de la camisa = x

Primer descuento obtenido = 20%

Precio pagado después de un descuento adicional del 15%

Primer descuento:

(1 - 0,20) * x = 0,8x

Segundo descuento:

(1 - 0,15) * 0,8x = 510

0,85 * 0,8x = 510

0,68x = 510

x = 510 / 0,68

x = $ 750

7 0

2 years ago

Inverse answer please

insens350 [35]

The inverse

⫘⫘⫘⫘⫘⫘⫘⫘⫘⫘⫘⫘

5 0

2 years ago

PLEASE HELP (30 POINTS) Solve the rational equation x/3 = x^2/x + 5 , and check for extraneous solutions.

anygoal [31]

Option C: $x=0$ and $x=\frac{5}{2}$ are the solutions.

Explanation:

The equation is $\frac{x}{3} =\frac{x^{2} }{x+5}$

We shall determine the value of x, by simplifying the equation.

$\begin{aligned} x(x+5) &=3 x^{2} \\ x^{2}+5 x &=3 x^{2} \\ 2 x^{2}-5 x &=0 \\ x(2 x-5) &=0 \end{aligned}$

Thus, $x=0$ and $x=\frac{5}{2}$ are the solutions.

Now, let us check whether the solutions are extraneous solutions.

Let us substitute $x=0$ in the original equation to check whether both sides of the equation are equal.

$\begin{aligned}&\frac{0}{3}=\frac{0^{2}}{0+5}\\&0=\frac{0}{5}\\&0=0\end{aligned}$

Thus, both sides of the equation are equal.

Hence $x=0$ is a true solution.

Now, Let us substitute $x=\frac{5}{2}$ in the original equation to check whether both sides of the equation are equal.

$\begin{aligned}\frac{\left(\frac{5}{2}\right)}{3} &=\frac{\left(\frac{5}{2}\right)^{2}}{\left(\frac{5}{2}\right)+5} \\\frac{5}{6} &=\frac{\left(\frac{25}{4}\right)}{\left(\frac{15}{2}\right)} \\\frac{5}{6} &=\frac{5}{6}\end{aligned}$

Thus, both sides of the equation are equal.

Hence, $x=\frac{5}{2}$ is a true solution.

Thus, solutions are not extraneous.

Hence, Option C is the correct answer.

8 0

3 years ago